Solution Manual for Fluid Mech Cengel Book

Chapter 6 Momentum Analysis of Flow Systems Chapter 6 MOMENTUM ANALYSIS OF FLOW SYSTEMS Newton’s Laws and Conservation of Momentum 6-1C Newton’s first law states that â€Å"a body at rest remains at rest, and a body in motion remains in motion at the same velocity in a straight path when the net force acting on it is zero. † Therefore, a body tends to preserve its state or inertia. Newton’s second law states that â€Å"the acceleration of a body is proportional to the net force acting on it and is inversely proportional to its mass. Newton’s third law states â€Å"when a body exerts a force on a second body, the second body exerts an equal and opposite force on the first. † r 6-2C Since momentum ( mV ) is the product of a vector (velocity) and a scalar (mass), momentum must be a vector that points in the same direction as the velocity vector. 6-3C The conservation of momentum principle is expressed as â€Å"the momentum of a system remains constant when the net force acting on it is zero, and thus the momentum of such systems is conserved†.The momentum of a body remains constant if the net force acting on it is zero. 6-4C Newton’s second law of motion, also called the angular momentum equation, is expressed as â€Å"the rate of change of the angular momentum of a body is equal to the net torque acting it. † For a non-rigid body with zero net torque, the angular momentum remains constant, but the angular velocity changes in accordance with I? = constant where I is the moment of inertia of the body. 6-5C No.Two rigid bodies having the same mass and angular speed will have different angular momentums unless they also have the same moment of inertia I. Linear Momentum Equation 6-6C The relationship between the time rates of change of an extensive property for a system and for a control volume is expressed by the Reynolds transport theorem, which provides the link between the r system and control volume concepts. The linear momentum equation is obtained by setting b = V and thus r B = mV in the Reynolds transport theorem. -7C The forces acting on the control volume consist of body forces that act throughout the entire body of the control volume (such as gravity, electric, and magnetic forces) and surface forces that act on the control surface (such as the pressure forces and reaction forces at points of contact). The net force acting on a control volume is the sum of all body and surface forces. Fluid weight is a body force, and pressure is a surface force (acting per unit area). -8C All of these surface forces arise as the control volume is isolated from its surroundings for analysis, and the effect of any detached object is accounted for by a force at that location. We can minimize the number of surface forces exposed by choosing the control volume such that the forces that we are not interested in remain internal, and thus they do not complicate the analysis. A well-chosen cont rol volume exposes only the forces that are to be determined (such as reaction forces) and a minimum number of other forces. 6-9C The momentum-flux correction factor ? nables us to express the momentum flux in terms of the r r r r & ? V (V ? n )dAc = ? mV avg . The value of ? is unity for uniform mass flow rate and mean flow velocity as ? Ac flow, such as a jet flow, nearly unity for turbulent flow (between 1. 01 and 1. 04), but about 1. 3 for laminar flow. So it should be considered in laminar flow. 6-1 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission.Chapter 6 Momentum Analysis of Flow Systems 6-10C The momentum equation for steady one-dimensional flow for the case of no external forces is r r r & & F= ? mV ? ? mV ? ? out ? in where the left hand side is the net force acting on the control volume, and first term on the right hand side is the incoming momentum flux and the second term is the outgoing momentum flux by mass. 6-11C In the application of the momentum equation, we can disregard the atmospheric pressure and work with gage pressures only since the atmospheric pressure acts in all directions, and its effect cancels out in every direction. -12C The fireman who holds the hose backwards so that the water makes a U-turn before being discharged will experience a greater reaction force since the numerical values of momentum fluxes across the nozzle are added in this case instead of being subtracted. 6-13C No, V is not the upper limit to the rocket’s ultimate velocity. Without friction the rocket velocity will continue to increase as more gas outlets the nozzle. 6-14C A helicopter hovers because the strong downdraft of air, caused by the overhead propeller blades, manifests a momentum in the air stream.This momentum must be countered by the helicopter lift force. 6-15C As the air density decreases, it requires more energy for a helicopter to hover, because more air must be forced into the downdraft by the helicopter blades to provide the same lift force. Therefore, it takes more power for a helicopter to hover on the top of a high mountain than it does at sea level. 6-16C In winter the air is generally colder, and thus denser. Therefore, less air must be driven by the blades to provide the same helicopter lift, requiring less power. 6-2 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc.Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-17C The force required to hold the plate against the horizontal water stream will increase by a factor of 4 when the velocity is doubled since & F = mV = ( ? AV )V = ? AV 2 and thus the force is proportional to the square of the velocity. 6-18C The accele ration will not be constant since the force is not constant. The impulse force exerted by & water on the plate is F = mV = ( ? AV )V = ?AV 2 , where V is the relative velocity between the water and the plate, which is moving. The plate acceleration will be a = F/m. But as the plate begins to move, V decreases, so the acceleration must also decrease. 6-19C The maximum velocity possible for the plate is the velocity of the water jet. As long as the plate is moving slower than the jet, the water will exert a force on the plate, which will cause it to accelerate, until terminal jet velocity is reached. 6-20 It is to be shown that the force exerted by a liquid jet of velocity V on a stationary nozzle is & proportional to V2, or alternatively, to m 2 . Assumptions 1 The flow is steady and incompressible. 2 The nozzle is given to be stationary. 3 The nozzle involves a 90 ° turn and thus the incoming and outgoing flow streams are normal to each other. 4 The water is discharged to the atmo sphere, and thus the gage pressure at the outlet is zero. Analysis We take the nozzle as the control volume, and the flow direction at the outlet as the x axis. Note that the nozzle makes a 90 ° turn, and thus it does not contribute to any pressure force or momentum flux & term at the inlet in the x direction. Noting that m = ?AV where A is the nozzle outlet area and V is the average nozzle outlet velocity, the momentum equation for steady one-dimensional flow in the x direction reduces to r r r & & & & F= ? mV ? ? mV > FRx = ? m out V out = ? mV ? ? out ? in where FRx is the reaction force on the nozzle due to liquid jet at the nozzle outlet. Then, & m = ? AV & > FRx = ? mV = AVV = AV 2 & & or FRx = ? mV = ? m & & m m2 =? ?A ? A Therefore, the force exerted by a liquid jet of velocity V on this & stationary nozzle is proportional to V2, or alternatively, to m 2 . Liquid Nozzle V FR 6-3 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc.Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-21 A water jet of velocity V impinges on a plate moving toward the water jet with velocity ? V. The force required to move the plate towards the jet is to be determined in terms of F acting on the stationary plate. Assumptions 1 The flow is steady and incompressible. 2 The plate is vertical and the jet is normal to plate. 3 The pressure on both sides of the plate is atmospheric pressure (and thus its effect cancels out). Fiction during motion is negligible. 5 There is no acceleration of the plate. 6 The water splashes off the sides of the plate in a plane normal to the jet. 6 Jet flow is nearly uniform and thus the effect of the momentum-flux correction factor is negligible, ? ? 1. Analysis We take the plate as the control volume. The relative velocity between the plate and the jet is V when the plate is st ationary, and 1. 5V when the plate is moving with a velocity ? V towards the plate. Then the momentum equation for steady one-dimensional flow in the horizontal direction reduces to r r r & & & & F= ? mV ? ? mV > ? FR = ? mi Vi > FR = miVi ? out ? in Stationary plate: ( Vi = V and Moving plate: ( Vi = 1. 5V and & mi = ? AVi = ? AV ) > FR = ? AV 2 = F & mi = ? AVi = ? A(1. 5V ) ) > FR = ? A(1. 5V ) 2 = 2. 25 ? AV 2 = 2. 25 F Therefore, the force required to hold the plate stationary against the oncoming water jet becomes 2. 25 times when the jet velocity becomes 1. 5 times. Discussion Note that when the plate is stationary, V is also the jet velocity. But if the plate moves toward the stream with velocity ? V, then the relative velocity is 1. 5V, and the amount of mass striking the plate (and falling off its sides) per unit time also increases by 50%. 1/2V VWaterjet 6-4 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-22 A 90 ° elbow deflects water upwards and discharges it to the atmosphere at a specified rate. The gage pressure at the inlet of the elbow and the anchoring force needed to hold the elbow in place are to be determined. v Assumptions 1 The flow is steady, frictionless, incompressible, and irrotational (so that the Bernoulli equation is applicable). The weight of the elbow and the water in it is negligible. 3 The water is discharged to the atmosphere, and thus the gage pressure at the outlet is zero. 4 The momentum-flux correction factor for each inlet and outlet is given to be ? = 1. 03. Properties We take the density of water to be 1000 kg/m3. Analysis (a) We take the elbow as the control volume, and designate the entrance by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of flow as being the positive direction) and the vertical coordinate by z.The continuity equation for this one-inlet one-outlet steady flow system is & & & & m1 = m 2 = m = 30 kg/s. Noting that m = ? AV , the mean inlet and outlet velocities of water are & & 25 kg/s m m = = = 3. 18 m/s 2 ? A ? (? D / 4) (1000 kg/m 3 )[? (0. 1 m) 2 / 4] Noting that V1 = V2 and P2 = Patm, the Bernoulli equation for a streamline going through the center of the reducing elbow is expressed as V1 = V 2 = V = P V12 P V2 1 + + z1 = 2 + 2 + z2 > P ? P2 = ? g ( z2 ? z1 ) > P , gage = ? g ( z2 ? z1 ) 1 1 ? g 2 g ? g 2 g Substituting, ? ? 1 kN 2 ? P , gage = (1000 kg/m3 )(9. 81 m/s 2 )(0. 35 m)? 1 ? 1000 kg ? /s2 ? = 3. 434 kN/m = 3. 434 kPa ? ? r r r & & (b) The momentum equation for steady one-dimensional flow is F= ? mV ? ? mV . We let the x- ? ? out ? in and z- components of the anchoring force of the elbow be FRx and FRz, and assume them to be in the positive directions. We also use gage pressures to avoid dealing with the atmospheric pressure which acts on all surfaces. Then the momentum equations along the x and y axes become & & FRx + P1,gage A1 = 0 ? ?m(+V1 ) = ? ?mV & & FRz = ? m(+V 2 ) = ? mV z x FRz 2 35 cm Solving for FRx and FRz, and substituting the given values, & FRx = ? ?mV ? P1, gage A1 ? N = ? 1. 03(25 kg/s)(3. 18 m/s)? ? 1 kg ? m/s 2 ? = ? 109 N ? ? ? (3434 N/m 2 )[? (0. 1 m) 2 / 4] ? ? ? ? = 81. 9 N ? ? FRy FRx = tan -1 Water 25 kg/s FRx 1 ? 1N & FRy = ? mV = 1. 03(25 kg/s)(3. 18 m/s)? ? 1 kg ? m/s 2 ? and 2 2 FR = FRx + FRy = (? 109) 2 + 81. 9 2 = 136 N, ? = tan -1 81. 9 = ? 37 ° = 143 ° ? 109 Discussion Note that the magnitude of the anchoring force is 136 N, and its line of action makes 143 ° from the positive x direction. Also, a negative value for FRx indicates the assumed direction is wrong, and should be reversed. 6-5 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc.Limited distribution permitted only to teachers and educators for course preparatio n. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-23 An 180 ° elbow forces the flow to make a U-turn and discharges it to the atmosphere at a specified rate. The gage pressure at the inlet of the elbow and the anchoring force needed to hold the elbow in place are to be determined. v Assumptions 1 The flow is steady, frictionless, one-dimensional, incompressible, and irrotational (so that the Bernoulli equation is applicable). The weight of the elbow and the water in it is negligible. 3 The water is discharged to the atmosphere, and thus the gage pressure at the outlet is zero. 4 The momentumflux correction factor for each inlet and outlet is given to be ? = 1. 03. Properties We take the density of water to be 1000 kg/m3. Analysis (a) We take the elbow as the control volume, and designate the entrance by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of flow as b eing the positive direction) and the vertical coordinate by z.The continuity equation for this one-inlet one-outlet steady flow system is & & & & m1 = m 2 = m = 30 kg/s. Noting that m = ? AV , the mean inlet and outlet velocities of water are & & 25 kg/s m m = = = 3. 18 m/s 2 ? A ? (? D / 4) (1000 kg/m 3 )[? (0. 1 m) 2 / 4] Noting that V1 = V2 and P2 = Patm, the Bernoulli equation for a streamline going through the center of the reducing elbow is expressed as V1 = V 2 = V = P V12 P V2 1 + + z1 = 2 + 2 + z2 > P ? P2 = ? g ( z2 ? z1 ) > P , gage = ? g ( z2 ? z1 ) 1 1 ? g 2 g ? g 2 g Substituting, ? ? 1 kN 2 ? P , gage = (1000 kg/m3 )(9. 81 m/s2 )(0. 70 m)? 1 ? 1000 kg ? m/s2 ? 6. 867 kN/m = 6. 867 kPa ? ? r r r & & (b) The momentum equation for steady one-dimensional flow is F= ? mV ? ? mV . We let the x- ? ? out ? in and z- components of the anchoring force of the elbow be FRx and FRz, and assume them to be in the positive directions. We also use gage pressures to avoid dealing with the atmospheric pressure which acts on all surfaces. Then the momentum equations along the x and z axes become & & & FRx + P1,gage A1 = ? m(? V 2 ) ? ? m(+V1 ) = ? 2 ? mV FRz = 0 Solving for FRx and substituting the given values, & FRx = ? 2 ? mV ? P1, gage A1 ? 1N = ? 2 ? 1. 03(25 kg/s)(3. 18 m/s)? 1 kg ? m/s 2 ? = ? 218 N ? ? ? (6867 N/m 2 )[? (0. 1 m) 2 / 4] ? ? 2 z x FRz Water 25 kg/s 35 cm and FR = FRx = – 218 N since the y-component of the anchoring force is zero. Therefore, the anchoring force has a magnitude of 218 N and it acts in the negative x direction. Discussion Note that a negative value for FRx indicates the assumed direction is wrong, and should be reversed. FRx 1 6-6 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission.Chapter 6 Momentum Analysis of Flow Systems 6-24E A horizontal water j et strikes a vertical stationary plate normally at a specified velocity. For a given anchoring force needed to hold the plate in place, the flow rate of water is to be determined. Assumptions 1 The flow is steady and incompressible. 2 The water splatters off the sides of the plate in a plane normal to the jet. 3 The water jet is exposed to the atmosphere, and thus the pressure of the water jet and the splattered water is the atmospheric pressure which is disregarded since it acts on the entire control surface. The vertical forces and momentum fluxes are not considered since they have no effect on the horizontal reaction force. 5 Jet flow is nearly uniform and thus the effect of the momentum-flux correction factor is negligible, ? ? 1. Properties We take the density of water to be 62. 4 lbm/ft3. Analysis We take the plate as the control volume such that it contains the entire plate and cuts through the water jet and the support bar normally, and the direction of flow as the positive direction of x axis. The momentum equation for steady one-dimensional flow in the x (flow) direction reduces in this case o r r r & & & & F= ? mV ? ? mV > ? FRx = ? mV1 > FR = mV1 ? ? out ? in We note that the reaction force acts in the opposite direction to flow, and we should not forget the negative & sign for forces and velocities in the negative x-direction. Solving for m and substituting the given values, & m= FRx 350 lbf = V1 30 ft/s ? 32. 2 lbm ? ft/s 2 ? ? 1 lbf ? ? ? = 376 lbm/s ? ? Then the volume flow rate becomes V& = & m ? = 376 lbm/s 62. 4 lbm/ft 3 = 6. 02 ft 3 /s Therefore, the volume flow rate of water under stated assumptions must be 6. 02 ft3/s.Discussion In reality, some water will be scattered back, and this will add to the reaction force of water. The flow rate in that case will be less. m 1 FRx = 350 lbf Waterjet 6-7 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparati on. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-25 A reducing elbow deflects water upwards and discharges it to the atmosphere at a specified rate.The anchoring force needed to hold the elbow in place is to be determined. v Assumptions 1 The flow is steady, frictionless, one-dimensional, incompressible, and irrotational (so that the Bernoulli equation is applicable). 2 The weight of the elbow and the water in it is considered. 3 The water is discharged to the atmosphere, and thus the gage pressure at the outlet is zero. 4 The momentumflux correction factor for each inlet and outlet is given to be ? = 1. 03. Properties We take the density of water to be 1000 kg/m3. Analysis The weight of the elbow and the water in it is W = mg = (50 kg)(9. 1 m/s 2 ) = 490. 5 N = 0. 4905 kN We take the elbow as the control volume, and designate the entrance by 1 and the outlet by 2. We also designate the horizontal coordina te by x (with the direction of flow as being the positive direction) and the vertical coordinate by z. The continuity equation for this one-inlet one-outlet steady flow system is & & & & m1 = m 2 = m = 30 kg/s. Noting that m = ? AV , the inlet and outlet velocities of water are & 30 kg/s m V1 = = = 2. 0 m/s ? A1 (1000 kg/m 3 )(0. 0150 m 2 ) & 30 kg/s m V2 = = = 12 m/s ? A2 (1000 kg/m 3 )(0. 025 m 2 ) Taking the center of the inlet cross section as the reference level (z1 = 0) and noting that P2 = Patm, the Bernoulli equation for a streamline going through the center of the reducing elbow is expressed as ? V 2 ? V12 ? ? V22 ? V12 ? P V12 P V2 1 ? ? ? + + z1 = 2 + 2 + z2 > P ? P2 = ? g ? 2 1 1 ? 2 g + z2 ? z1 ? > P , gage = ? g ? 2 g + z2 ? ?g 2 g ? g 2 g ? ? ? ? Substituting, ? (12 m/s) 2 ? (2 m/s) 2 ? 1 kN ? = 73. 9 kN/m 2 = 73. 9 kPa P , gage = (1000 kg/m3 )(9. 81 m/s 2 )? + 0. 4 1 2 ? 1000 kg ? m/s 2 ? 2(9. 81 m/s ) ? ? The momentum equation for steady one-dimensional flow is & & ? F = ? mV ? ? ? mV . We let the x- and out in r r r z- components of the anchoring force of the elbow be FRx and FRz, and assume them to be in the positive directions. We also use gage pressures to avoid dealing with the atmospheric pressure which acts on all surfaces. Then the momentum equations along the x and z axes become & & & FRx + P1,gage A1 = ? mV 2 cos ? ? ? mV1 and FRz ? W = ? mV 2 sin ? 2 25 cm2 Solving for FRx and FRz, and substituting the given values, & FRx = ? m(V 2 cos ? ? V1 ) ? P1, gage A1 ? 1 kN = 1. 03(30 kg/s)[(12cos45 ° – 2) m/s]? ? 1000 kg ? m/s 2 ? ? (73. 9 kN/m 2 )(0. 0150 m 2 ) = ? 0. 908 kN ? ? ? Water 30 kg/s 45 ° FRz FRx 150 m2 W 1 ? ? 1 kN ? & FRz = ? mV 2 sin ? + W = 1. 03(30 kg/s)(12sin45 ° m/s)? ? 1000 kg ? m/s 2 ? + 0. 4905 kN = 0. 753 kN ? ? 0. 753 2 2 2 2 -1 FRz FR = FRx + FRz = (? 0. 908) + (0. 753) = 1. 18 kN, ? = tan = tan -1 = ? 39. 7 ° FRx ? 0. 908 Discussion Note that the magnitude of the anchoring force is 1. 18 kN, and its line of action makes –39. 7 ° from +x direction. Negative value for FRx indicates the assumed direction is wrong. 6-8 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation.If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-26 A reducing elbow deflects water upwards and discharges it to the atmosphere at a specified rate. The anchoring force needed to hold the elbow in place is to be determined. v Assumptions 1 The flow is steady, frictionless, one-dimensional, incompressible, and irrotational (so that the Bernoulli equation is applicable). 2 The weight of the elbow and the water in it is considered. 3 The water is discharged to the atmosphere, and thus the gage pressure at the outlet is zero. The momentumflux correction factor for each inlet and outlet is given to be ? = 1. 03. Properties We take the densi ty of water to be 1000 kg/m3. Analysis The weight of the elbow and the water in it is W = mg = (50 kg)(9. 81 m/s 2 ) = 490. 5 N = 0. 4905 kN We take the elbow as the control volume, and designate the entrance by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of flow as being the positive direction) and the vertical coordinate by z. The continuity equation for this one-inlet one-outlet steady flow system is & & & & m1 = m 2 = m = 30 kg/s. Noting that m = ?AV , the inlet and outlet velocities of water are & 30 kg/s m = = 2. 0 m/s V1 = ? A1 (1000 kg/m 3 )(0. 0150 m 2 ) & 30 kg/s m V2 = = = 12 m/s ? A2 (1000 kg/m 3 )(0. 0025 m 2 ) Taking the center of the inlet cross section as the reference level (z1 = 0) and noting that P2 = Patm, the Bernoulli equation for a streamline going through the center of the reducing elbow is expressed as ? V 2 ? V12 ? ? V22 ? V12 ? P V12 P V2 1 ? ? ? + + z1 = 2 + 2 + z2 > P ? P2 = ? g ? 2 1 1 ? 2 g + z2 ? z1 ? > P , gage = ? g ? 2 g + z2 ? ?g 2 g ? g 2 g ? ? ? ? or, P , gage = (1000 kg/m3 )(9. 81 m/s2 )? 1 ? ? ? (12 m/s)2 ? (2 m/s)2 2(9. 81 m/s ) ? 1 kN ? = 73. 9 kN/m 2 = 73. 9 kPa + 0. 4 1000 kg ? m/s 2 ? ? The momentum equation for steady one-dimensional flow is & & ? F = ? ?mV ? ? ? mV . We let the xout in r r r and y- components of the anchoring force of the elbow be FRx and FRz, and assume them to be in the positive directions. We also use gage pressures to avoid dealing with the atmospheric pressure which acts on all surfaces. Then the momentum equations along the x and z axes become & & FRx + P1,gage A1 = ? mV 2 cos ? ? ? mV1 and & FRy ? W = ? mV 2 sin ? Solving for FRx and FRz, and substituting the given values, & FRx = ? m(V 2 cos ? V1 ) ? P1, gage A1 ? 1 kN = 1. 03(30 kg/s)[(12cos110 ° – 2) m/s]? ? 1000 kg ? m/s 2 ? FRz ? ? ? (73. 9 kN/m 2 )(0. 0150 m 2 ) = ? 1. 297 kN ? ? ? ? 1 kN ? + 0. 4905 kN = 0. 8389 kN & = ? mV 2 sin ? + W = 1. 03(30 kg/s)(12sin110 ° m/s)? 2 ? ? 1000 kg ? m/s ? ? 2 25 cm2 110 ° 2 2 FR = FRx + FRz = (? 1. 297) 2 + 0. 8389 2 = 1. 54 kN and FRz 0. 8389 = tan -1 = ? 32. 9 ° FRx ? 1. 297 Discussion Note that the magnitude of the anchoring force is 1. 54 kN, and its line of action makes –32. 9 ° from +x direction. Negative value for FRx indicates assumed direction is wrong, and should be reversed. ? = tan -1 FRz FRx Water 1 30 kg/s 50 m2 W 6-9 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-27 Water accelerated by a nozzle strikes the back surface of a cart moving horizontally at a constant velocity. The braking force and the power wasted by the brakes are to be determined. . Assumptions 1 The flow is steady and incompressible. 2 The water splatters off the sides of the plate in all direction s in the plane of the back surface. The water jet is exposed to the atmosphere, and thus the pressure of the water jet and the splattered water is the atmospheric pressure which is disregarded since it acts on all surfaces. 4 Fiction during motion is negligible. 5 There is no acceleration of the cart. 7 The motions of the water jet and the cart are horizontal. 6 Jet flow is nearly uniform and thus the effect of the momentum-flux correction factor is negligible, ? ? 1. Analysis We take the cart as the control volume, and the direction of flow as the positive direction of x axis. The relative velocity between the cart and the jet is V r = V jet ?Vcart = 15 ? 10 = 10 m/s 15 m/s 5 m/s Therefore, we can assume the cart to be stationary and the jet to move Waterjet with a velocity of 10 m/s. The momentum equation for steady onedimensional flow in the x (flow) direction reduces in this case to r r r & & & & F= ? mV ? ? mV > FRx = ? mi Vi > Fbrake = ? mV r FRx ? ? out ? in We note that the brake force acts in the opposite direction to flow, and we should not forget the negative sign for forces and velocities in the negative x-direction. Substituting the given values, ? 1N & Fbrake = ? mV r = ? (25 kg/s)(+10 m/s)? ? 1 kg ? m/s 2 ? ? ? = ? 250 N ? ?The negative sign indicates that the braking force acts in the opposite direction to motion, as expected. Noting that work is force times distance and the distance traveled by the cart per unit time is the cart velocity, the power wasted by the brakes is 1 kW ? ? & W = FbrakeV cart = (250 N)(5 m/s)? ? = 1. 25 kW ? 1000 N ? m/s ? Discussion Note that the power wasted is equivalent to the maximum power that can be generated as the cart velocity is maintained constant. 6-10 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation.If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Fl ow Systems 6-28 Water accelerated by a nozzle strikes the back surface of a cart moving horizontally. The acceleration of the cart if the brakes fail is to be determined. Analysis The braking force was determined in previous problem to be 250 N. When the brakes fail, this force will propel the cart forward, and the accelerating will be a= F 250 N ? 1 kg ? m/s 2 ? = m cart 300 kg ? 1N ? ? ? = 0. 833 m/s 2 ? ? Discussion This is the acceleration at the moment the brakes fail.The acceleration will decrease as the relative velocity between the water jet and the cart (and thus the force) decreases. 5 m/s 15 m/s 300 kg Waterjet FRx 6-11 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-29E A water jet hits a stationary splitter, such that half of the flow is diverted up ward at 45 °, and the other half is directed down.The force required to hold the splitter in place is to be determined. vEES Assumptions 1 The flow is steady and incompressible. 2 The water jet is exposed to the atmosphere, and thus the pressure of the water jet before and after the split is the atmospheric pressure which is disregarded since it acts on all surfaces. 3 The gravitational effects are disregarded. 4 Jet flow is nearly uniform and thus the effect of the momentum-flux correction factor is negligible, ? ? 1. Properties We take the density of water to be 62. 4 lbm/ft3. Analysis The mass flow rate of water jet is & & m = ? V = (62. lbm/ft 3 )(100 ft 3 /s) = 6240 lbm/s We take the splitting section of water jet, including the splitter as the control volume, and designate the entrance by 1 and the outlet of either arm by 2 (both arms have the same velocity and mass flow rate). We also designate the horizontal coordinate by x with the direction of flow as being the positive direction and the vertical coordinate by z. r r r & & The momentum equation for steady one-dimensional flow is F= ? mV ? ? mV . We let ? ? out ? in the x- and y- components of the anchoring force of the splitter be FRx and FRz, and assume them to be in the & & positive directions.Noting that V2 = V1 = V and m 2 = 1 m , the momentum equations along the x and z 2 axes become & & & FRx = 2( 1 m)V 2 cos ? ? mV1 = mV (cos ? ? 1) 2 & & FRz = 1 m(+V 2 sin ? ) + 1 m(? V 2 sin ? ) ? 0 = 0 2 2 Substituting the given values, 1 lbf ? ? FRx = (6240 lbm/s)(20 ft/s)(cos45 ° – 1)? ? = ? 1135 lbf 32. 2 lbm ? ft/s 2 ? ? FRz = 0 The negative value for FRx indicates the assumed direction is wrong, and should be reversed. Therefore, a force of 1135 lbf must be applied to the splitter in the opposite direction to flow to hold it in place. No holding force is necessary in the vertical direction.This can also be concluded from the symmetry. Discussion In reality, the gravitational effects will cau se the upper stream to slow down and the lower stream to speed up after the split. But for short distances, these effects are indeed negligible. 20 ft/s 100 ft/s FRz 45 ° 45 ° FRx 6-12 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-30E Problem 6-29E is reconsidered.The effect of splitter angle on the force exerted on the splitter as the half splitter angle varies from 0 to 180 ° in increments of 10 ° is to be investigated. g=32. 2 â€Å"ft/s2† rho=62. 4 â€Å"lbm/ft3† V_dot=100 â€Å"ft3/s† V=20 â€Å"ft/s† m_dot=rho*V_dot F_R=-m_dot*V*(cos(theta)-1)/g â€Å"lbf† ?,  ° 0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 180 8000 7000 6000 5000 & m , lbm/s 6240 6240 6240 6240 6240 6240 6240 6240 6240 6240 624 0 6240 6240 6240 6240 6240 6240 6240 6240 FR, lbf 0 59 234 519 907 1384 1938 2550 3203 3876 4549 5201 5814 6367 6845 7232 7518 7693 7752 FR, lbf 000 3000 2000 1000 0 0 20 40 60 80 100 120 140 160 180 ?,  ° 6-13 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-31 A horizontal water jet impinges normally upon a vertical plate which is held on a frictionless track and is initially stationary. The initial acceleration of the plate, the time it takes to reach a certain velocity, and the velocity at a given time are to be determined.Assumptions 1 The flow is steady and incompressible. 2 The water always splatters in the plane of the retreating plate. 3 The water jet is exposed to the atmosphere, and thus the pressure of the water jet and the splattered water is the a tmospheric pressure which is disregarded since it acts on all surfaces. 4 The tract is nearly frictionless, and thus fiction during motion is negligible. 5 The motions of the water jet and the cart are horizontal. 6 The velocity of the jet relative to the plate remains constant, Vr = Vjet = V. 7 Jet flow is nearly uniform and thus the effect of the momentum-flux correction factor is egligible, ? ? 1. Properties We take the density of water to be 1000 kg/m3. Analysis (a) We take the vertical plate on the frictionless track as the control volume, and the direction of flow as the positive direction of x axis. The mass flow rate of water in the jet is & m = ? VA = (1000 kg/m 3 )(18 m/s)[? (0. 05 m) 2 / 4] = 35. 34 kg/s The momentum equation for steady one-dimensional flow in the x (flow) direction reduces in this case to r r r & & & & F= ? mV ? ? mV > FRx = ? mi Vi > FRx = ? mV ? ? out ? in where FRx is the reaction force required to hold the plate in place.When the plate is released, a n equal and opposite impulse force acts on the plate, which is determined to ? 1N & Fplate = ? FRx = mV = (35. 34 kg/s)(18 m/s)? ? 1 kg ? m/s 2 ? ? ? = 636 N ? ? Then the initial acceleration of the plate becomes a= Fplate m plate = 636 N ? 1 kg ? m/s 2 ? 1000 kg ? 1 N ? ? ? = 0. 636 m/s 2 ? ? 18 m/s 1000 kg Waterjet Frictionless track This acceleration will remain constant during motion since the force acting on the plate remains constant. (b) Noting that a = dV/dt = ? V/? t since the acceleration a is constant, the time it takes for the plate to reach a velocity of 9 m/s is ? t = ? V plate a = (9 ? ) m/s 0. 636 m/s 2 FRx = 14. 2 s (c) Noting that a = dV/dt and thus dV = adt and that the acceleration a is constant, the plate velocity in 20 s becomes V plate = V0, plate + a? t = 0 + (0. 636 m/s 2 )(20 s) = 12. 7 m/s Discussion The assumption that the relative velocity between the water jet and the plate remains constant is valid only for the initial moments of motion when the plate velocity is low unless the water jet is moving with the plate at the same velocity as the plate. 6-14 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation.If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-32 A 90 ° reducer elbow deflects water downwards into a smaller diameter pipe. The resultant force exerted on the reducer by water is to be determined. Assumptions 1 The flow is steady, frictionless, one-dimensional, incompressible, and irrotational (so that the Bernoulli equation is applicable). 2 The weight of the elbow and the water in it is disregarded since the gravitational effects are negligible. 3 The momentum-flux correction factor for each inlet and outlet is given to be ? 1. 04. Properties We take the density of water to be 1000 kg/m3. Analysis We take the elbow as the control volume, and designate the entrance by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of flow as being the positive direction) and the vertical coordinate by z. The continuity equation for this one-inlet one-outlet steady flow system is & & & & m1 = m 2 = m = 353. 4 kg/s. Noting that m = ? AV , the mass flow rate of water and its outlet velocity are 2 & m = ? V1 A1 = ? V1 (? D1 / 4) = (1000 kg/m 3 )(5 m/s)[? (0. 3 m) 2 / 4] = 353. 4 kg/s & & 353. kg/s m m = = = 20 m/s 2 ? A2 D 2 / 4 (1000 kg/m 3 )[? (0. 15 m) 2 / 4] The Bernoulli equation for a streamline going through the center of the reducing elbow is expressed as V2 = P V12 P V2 1 + + z1 = 2 + 2 + z2 ? g 2 g ? g 2 g > ? V 2 ? V22 ? ? P2 = P + ? g ? 1 1 ? 2 g + z1 ? z2 ? ? ? Substituting, the gage pressure at the outlet becomes ? (5 m/s)2 ? (20 m/s)2 1 kPa ? 1 kN ? P2 = (300 kPa) + (1000 kg/m 3 )(9. 81 m/s 2 )? + 0. 5 = 117. 4 kPa 2 ? 1000 kg ? m/s 2 1 kN/m 2 ? 2(9. 81 m/s ) ? ? The momentum equation for steady one-dimensional flow is & & ? F = ? ?mV ? ? ? mV . We let the xout in r r and z- components of the anchoring force of the elbow be FRx and FRz, and assume them to be in the positive directions. Then the momentum equations along the x and z axes become & FRx + P1,gage A1 = 0 ? ? mV1 & FRz ? P2,gage A2 = ? m(? V 2 ) ? 0 Note that we should not forget the negative sign for forces and velocities in the negative x or z direction. Solving for FRx and FRz, and substituting the given values, ? 1 kN & FRx = ? ?mV1 ? P1, gage A1 = ? 1. 04(353. 4 kg/s)(5 m/s)? ? 1000 kg ? m/s 2 ? ? ? (0. 3 m) 2 ? ? (300 kN/m 2 ) = ? 23. 0 kN ? 4 ? ? ? (0. 15 m) 2 ? + (117. 4 kN/m 2 ) = ? 5. 28 kN ? ? FRz ? 1 kN & FRz = ? ? mV 2 + P2, gage A1 = ? 1. 04(353. 4 kg/s)(20 m/s)? ? 1000 kg ? m/s 2 ? and 2 2 FR = FRx + FRz = (? 23. 0) 2 + (? 5. 28) 2 = 23. 6 kN FRx 30 cm Water 5 m/s ? = tan -1 FRz ? 5. 28 = tan -1 = 12. 9 ° FRx ? 23. 0 Discussion The magnitude of the anchoring force is 23. 6 kN, and its line of action makes 12. 9 ° from +x direction. Negative values for FRx and FRy indicate that the assumed directions are wrong, and should be reversed. 15 cm 6-15 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation.If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-33 A wind turbine with a given span diameter and efficiency is subjected to steady winds. The power generated and the horizontal force on the supporting mast of the turbine are to be determined. vEES Assumptions 1 The wind flow is steady and incompressible. 2 The efficiency of the turbine-generator is independent of wind speed. 3 The frictional effects are negligible, and thus none of the incoming kinetic energy is converted to thermal energy. Wind flow is uniform and thus the momentum-flux correction factor is nearly unity, ? ? 1. Properties The density of air is given to be 1. 25 kg/m3. Analysis (a) The power potential of the wind is its kinetic energy, & which is V2/2 per unit mass, and mV 2 / 2 for a given mass flow rate: ? 1 m/s ? V1 = (25 km/h)? ? = 6. 94 m/s ? 3. 6 km/h ? & m = ? 1V1 A1 = ? 1V1 Wind V1 1 2 D V2 ?D 2 4 2 = (1. 25 kg/m 3 )(6. 94 m/s) ? (90 m) 2 4 2 = 55,200 kg/s V (6. 94 m/s) & & & W max = mke1 = m 1 = (55,200 kg/s) 2 2 ? 1 kN ? ? 1000 kg ? m/s 2 ? 1 kW ? 1 kN ? m/s ? = 1330 kW ? ? FR Then the actual power produced becomes & Wact = ? wind turbineW max = (0. 32)(1330 kW) = 426 kW (b) The frictional effects are assumed to be negligible, and thus the portion of incoming kinetic energy not converted to electric power leaves the wind turbine as outgoing kinetic energy. Therefore, V2 V2 & & & & mke 2 = mke1 (1 ? ? wind turbine ) > m 2 = m 1 (1 ? ? wind turbine ) 2 2 or V 2 = V1 1 ? ? wind turbine = (6. 94 m/s) 1 – 0. 32 = 5. 72 m/s We choose the control volume around the wind turbine such that the wind is norm al to the control surface at the inlet and the outlet, and the entire control surface is at the atmospheric pressure.The momentum r r r & & equation for steady one-dimensional flow is F= ? mV ? ? mV . Writing it along the x-direction ? ? out ? in (without forgetting the negative sign for forces and velocities in the negative x-direction) and assuming the flow velocity through the turbine to be equal to the wind velocity give ? 1 kN & & & FR = mV 2 ? mV1 = m(V 2 ? V1 ) = (55,200 kg/s)(5. 72 – 6. 94 m/s)? ? 1000 kg ? m/s 2 ? ? ? = ? 67. 3 kN ? ? The negative sign indicates that the reaction force acts in the negative x direction, as expected.Discussion This force acts on top of the tower where the wind turbine is installed, and the bending moment it generates at the bottom of the tower is obtained by multiplying this force by the tower height. 6-16 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for c ourse preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-34E A horizontal water jet strikes a curved plate, which deflects the water back to its original direction.The force required to hold the plate against the water stream is to be determined. Assumptions 1 The flow is steady and incompressible. 2 The water jet is exposed to the atmosphere, and thus the pressure of the water jet and the splattered water is the atmospheric pressure, which is disregarded since it acts on all surfaces. 3 Friction between the plate and the surface it is on is negligible (or the friction force can be included in the required force to hold the plate). 4 There is no splashing of water or the deformation of the jet, and the reversed jet leaves horizontally at the same velocity and flow rate. Jet flow is nearly uniform and thus the momentum-flux correction factor is nearly unity, ? ? 1. Properties We take the density of w ater to be 62. 4 lbm/ft3. Analysis We take the plate together with the curved water jet as the control volume, and designate the jet inlet by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of incoming flow as being the positive direction). The continuity equation for this one-inlet one-outlet steady & & & flow system is m1 = m 2 = m where & m = ? VA = ? V [? D 2 / 4] = (62. 4 lbm/ft 3 )(140 ft/s)[? (3 / 12 ft) 2 / 4] = 428. lbm/s r r r & & The momentum equation for steady one-dimensional flow is F= ? mV ? ? mV . Letting the ? ? out ? in reaction force to hold the plate be FRx and assuming it to be in the positive direction, the momentum equation along the x axis becomes & & & FRx = m(? V 2 ) ? m(+V1 ) = ? 2mV Substituting, 1 lbf ? ? FRx = ? 2(428. 8 lbm/s)(140 ft/s)? ? = ? 3729 lbf 2 ? 32. 2 lbm ? ft/s ? Therefore, a force of 3729 lbm must be applied on the plate in the negative x direction to hold it in place. Discussion Note that a nega tive value for FRx indicates the assumed direction is wrong (as expected), and should be reversed.Also, there is no need for an analysis in the vertical direction since the fluid streams are horizontal. 2 140 ft/s Waterjet FRx 1 140 ft/s 3 in 6-17 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-35E A horizontal water jet strikes a bent plate, which deflects the water by 135 ° from its original direction. The force required to hold the plate against the water stream is to be determined.Assumptions 1 The flow is steady and incompressible. 2 The water jet is exposed to the atmosphere, and thus the pressure of the water jet and the splattered water is the atmospheric pressure, which is disregarded since it acts on all surfaces. 3 Frictional and gravitational effec ts are negligible. 4 There is no splattering of water or the deformation of the jet, and the reversed jet leaves horizontally at the same velocity and flow rate. 5 Jet flow is nearly uniform and thus the momentum-flux correction factor is nearly unity, ? ? 1. Properties We take the density of water to be 62. 4 lbm/ft3.Analysis We take the plate together with the curved water jet as the control volume, and designate the jet inlet by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of incoming flow as being the positive direction), and the vertical coordinate by z. The continuity equation for & & & this one-inlet one-outlet steady flow system is m1 = m 2 = m where & m = ? VA = ? V [? D 2 / 4] = (62. 4 lbm/ft 3 )(140 ft/s)[? (3 / 12 ft) 2 / 4] = 428. 8 lbm/s r r r & & The momentum equation for steady one-dimensional flow is F= ? mV ? ? mV . We let the x- ? ? out ? in nd z- components of the anchoring force of the plate be FRx and FRz, and assu me them to be in the positive directions. Then the momentum equations along the x and y axes become & & & FRx = m(? V 2 ) cos 45 ° ? m(+V1 ) = ? mV (1 + cos 45 °) & (+V 2 ) sin 45 ° = mV sin 45 ° & FRz = m Substituting the given values, 1 lbf ? ? FRx = ? 2(428. 8 lbm/s)(140 ft/s)(1 + cos45 °)? 2 ? ? 32. 2 lbm ? ft/s ? = ? 6365 lbf 1 lbf ? ? FRz = (428. 8 lbm/s)(140 ft/s)sin45 °? = 1318 lbf 2 ? ? 32. 2 lbm ? ft/s ? 2 140 ft/s Waterjet 135 ° FRz FRx 3 in 1 and 2 2 FR = FRx + FRz = (? 6365) 2 + 1318 2 = 6500 lbf , ? = tan -1 FRy FRx = tan -1 1318 = ? 1. 7 ° = 168. 3 ° ? 6365 Discussion Note that the magnitude of the anchoring force is 6500 lbf, and its line of action makes 168. 3 ° from the positive x direction. Also, a negative value for FRx indicates the assumed direction is wrong, and should be reversed. 6-18 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-36 Firemen are holding a nozzle at the end of a hose while trying to extinguish a fire.The average water outlet velocity and the resistance force required of the firemen to hold the nozzle are to be determined. Assumptions 1 The flow is steady and incompressible. 2 The water jet is exposed to the atmosphere, and thus the pressure of the water jet is the atmospheric pressure, which is disregarded since it acts on all surfaces. 3 Gravitational effects and vertical forces are disregarded since the horizontal resistance force is to be determined. 5 Jet flow is nearly uniform and thus the momentum-flux correction factor can be taken to be unity, ? ? 1. Properties We take the density of water to be 1000 kg/m3.Analysis (a) We take the nozzle and the horizontal portion of the hose as the system such that water enters the control volume vertically and outlets horizontally (thi s way the pressure force and the momentum flux at the inlet are in the vertical direction, with no contribution to the force balance in the horizontal direction), and designate the entrance by 1 and the outlet by 2. We also designate the horizontal coordinate by x (with the direction of flow as being the positive direction). The average outlet velocity and the mass flow rate of water are determined from V= V& A = V& ? D / 4 2 = 5 m 3 /min ? (0. 06 m) 2 / 4 1768 m/min = 29. 5 m/s & m = ? V& = (1000 kg/m 3 )(5 m 3 /min) = 5000 kg/min = 83. 3 kg/s (b) The momentum equation for steady one-dimensional flow is & & ? F = ? ?mV ? ? ? mV . We let out in r r r horizontal force applied by the firemen to the nozzle to hold it be FRx, and assume it to be in the positive x direction. Then the momentum equation along the x direction gives ? ? 1N ? = 2457 N & & FRx = mVe ? 0 = mV = (83. 3 kg/s)(29. 5 m/s)? ? 1kg ? m/s 2 ? ? ? Therefore, the firemen must be able to resist a force of 2457 N to hold t he nozzle in place. Discussion The force of 2457 N is equivalent to the weight of about 250 kg.That is, holding the nozzle requires the strength of holding a weight of 250 kg, which cannot be done by a single person. This demonstrates why several firemen are used to hold a hose with a high flow rate. FRz FRx 5 m3/min 6-19 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-37 A horizontal jet of water with a given velocity strikes a flat plate that is moving in the same direction at a specified velocity.The force that the water stream exerts against the plate is to be determined. Assumptions 1 The flow is steady and incompressible. 2 The water splatters in all directions in the plane of the plate. 3 The water jet is exposed to the atmosphere, and thus the pressure o f the water jet and the splattered water is the atmospheric pressure, which is disregarded since it acts on all surfaces. 4 The vertical forces and momentum fluxes are not considered since they have no effect on the horizontal force exerted on the plate. 5 The velocity of the plate, and the velocity of the water jet relative to the plate, are constant. Jet flow is nearly uniform and thus the momentum-flux correction factor can be taken to be unity, ? ? 1. Properties We take the density of water to be 1000 kg/m3. Analysis We take the plate as the control volume, and the flow direction as the positive direction of x axis. The mass flow rate of water in the jet is & m = ? V jet A = ? V jet 10 m/s 30 m/s FRx 5 cm Waterjet ?D 4 2 = (1000 kg/m 3 )(30 m/s) ? (0. 05 m) 2 4 = 58. 9 kg/s The relative velocity between the plate and the jet is V r = V jet ? V plate = 30 ? 10 = 20 m/s Therefore, we can assume the plate to be stationary and the jet to move with a velocity of 20 m/s.The r r r & & F= ? mV ? ? mV . We let the horizontal momentum equation for steady one-dimensional flow is ? ? out ? in reaction force applied to the plate in the negative x direction to counteract the impulse of the water jet be FRx. Then the momentum equation along the x direction gives ? ? 1N ? & & ? FRx = 0 ? mVi > FRx = mV r = (58. 9 kg/s)(20 m/s)? ? 1kg ? m/s 2 ? = 1178 N ? ? Therefore, the water jet applies a force of 1178 N on the plate in the direction of motion, and an equal and opposite force must be applied on the plate if its velocity is to remain constant.Discussion Note that we used the relative velocity in the determination of the mass flow rate of water in the momentum analysis since water will enter the control volume at this rate. (In the limiting case of the plate and the water jet moving at the same velocity, the mass flow rate of water relative to the plate will be zero since no water will be able to strike the plate). 6-20 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Comp anies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission.Chapter 6 Momentum Analysis of Flow Systems 6-38 Problem 6-37 is reconsidered. The effect of the plate velocity on the force exerted on the plate as the plate velocity varies from 0 to 30 m/s in increments of 3 m/s is to be investigated. rho=1000 â€Å"kg/m3† D=0. 05 â€Å"m† V_jet=30 â€Å"m/s† Ac=pi*D^2/4 V_r=V_jet-V_plate m_dot=rho*Ac*V_jet F_R=m_dot*V_r â€Å"N† Vplate, m/s 0 3 6 9 12 15 18 21 24 27 30 Vr, m/s 30 27 24 21 18 15 12 9 6 3 0 FR, N 1767 1590 1414 1237 1060 883. 6 706. 9 530. 1 353. 4 176. 7 0 1800 1600 1400 1200 1000 FR, N 800 600 400 200 0 0 5 10 15 20 25 30 Vplate, m/s 6-21PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you ar e using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-39E A fan moves air at sea level at a specified rate. The force required to hold the fan and the minimum power input required for the fan are to be determined. v Assumptions 1 The flow of air is steady and incompressible. 2 Standard atmospheric conditions exist so that the pressure at sea level is 1 atm. Air leaves the fan at a uniform velocity at atmospheric pressure. 4 Air approaches the fan through a large area at atmospheric pressure with negligible velocity. 5 The frictional effects are negligible, and thus the entire mechanical power input is converted to kinetic energy of air (no conversion to thermal energy through frictional effects). 6 Wind flow is nearly uniform and thus the momentum-flux correction factor can be taken to be unity, ? ? 1. Properties The gas constant of air is R = 0. 3704 psi? ft3/lbm? R. The standard atmospheric pressure at sea level is 1 atm = 14. 7 psi.Analysis (a) We take the control volume to be a horizontal hyperbolic cylinder bounded by streamlines on the sides with air entering through the large cross-section (section 1) and the fan located at the narrow cross-section at the end (section 2), and let its centerline be the x axis. The density, mass flow rate, and discharge velocity of air are 14. 7 psi P ? = = = 0. 0749 lbm/ft 3 RT (0. 3704 psi ? ft 3 /lbm ? R)(530 R) & m = ? V& = (0. 0749 lbm/ft 3 )(2000 ft 3/min) = 149. 8 lbm/min = 2. 50 lbm/s V2 = V& A2 = V& 2 ? D 2 / 4 = 2000 ft 3 /min ? (2 ft) 2 / 4 = 636. 6 ft/min = 10. ft/s & & ? F = ? ?mV ? ? ? mV . Letting the out in The momentum equation for steady one-dimensional flow is r r r reaction force to hold the fan be FRx and assuming it to be in the positive x (i. e. , the flow) direction, the momentum equation along the x axis becomes 1 lbf ? ? & & FRx = m(V 2 ) ? 0 = mV = (2. 50 lbm/s)(10. 6 ft/s)? ? = 0. 82 lbf 2 ? 32. 2 lbm ? ft/s ? Therefore, a force of 0. 82 lbf must be applied (through frict ion at the base, for example) to prevent the fan from moving in the horizontal direction under the influence of this force. (b) Noting that P1 = P2 = Patm and V1 ? , the energy equation for the selected control volume reduces to ?P V2 ? ?P V2 ? & & & & & m? 1 + 1 + gz1 ? + W pump, u = m? 2 + 2 + gz 2 ? + W turbine + E mech,loss > ? ? ? ? 2 2 ? ? ? ? Substituting, V & & Wfan, u = m 2 2 2 V2 (10. 6 ft/s) 2 ? 1 lbf 1W ? & & Wfan,u = m 2 = (2. 50 lbm/s) ? ? = 5. 91 W 2 2 2 ? 32. 2 lbm ? ft/s 0. 73756 lbf ? ft/s ? Therefore, a useful mechanical power of 5. 91 W must be supplied to 2000 cfm air. This is the minimum required power input required for the fan. Discussion The actual power input to the fan will be larger than 5. 1 W because of the fan inefficiency in converting mechanical power to kinetic energy. Fan 1 2 24 in 6-22 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-40 A helicopter hovers at sea level while being loaded. The volumetric air flow rate and the required power input during unloaded hover, and the rpm and the required power input during loaded hover are to be determined. Assumptions 1 The flow of air is steady and incompressible. 2 Air leaves the blades at a uniform velocity at atmospheric pressure. 3 Air approaches the blades from the top through a large area at atmospheric pressure with negligible velocity. 4 The frictional effects are negligible, and thus the entire mechanical power input is converted to kinetic energy of air (no conversion to thermal energy through frictional effects). 5 The change in air pressure with elevation is negligible because of the low density of air. 6 There is no acceleration of the helicopter, and thus the lift generated is equal to the total weight. Air flow is nearly uniform and thus the momentum-flux correction factor can be taken to be unity, ? ? 1. Properties The density of air is given to be 1. 18 kg/m3. Analysis (a) We take the control volume to be a vertical hyperbolic cylinder bounded by streamlines on the sides with air entering through the large cross-section (section 1) at the top and the fan located at the narrow cross-section at the bottom (section 2), and let its centerline be the z axis with upwards being the positive direction. r r r & & F= ? mV ? ? mV . Noting The momentum equation for steady one-dimensional flow is ? out ? in that the only force acting on the control volume is the total weight W and it acts in the negative z direction, the momentum equation along the z axis gives W & & ? W = m(? V 2 ) ? 0 > W = mV 2 = ( ? AV 2 )V 2 = ? AV 22 > V2 = ? A 1 where A is the blade span area, 15 m A = ? D / 4 = ? (15 m) / 4 = 176. 7 m 2 2 2 Then the discharge velocity, volume flow rate, and the mass flow rate of air in the unloaded mode become V 2,unloaded = m unloaded g = ? A (10,000 kg)(9. 81 m/s 2 ) (1. 18 kg/m 3 )(176. 7 m 2 ) = 21. 7 m/s Sea level 2 V&unloaded = AV 2,unloaded = (176. 7 m 2 )(21. m/s) = 3834 m 3 /s & munloaded = ? V&unloaded = (1. 18 kg/m 3 )(3834 m 3/s) = 4524 kg/s Load 15,000 kg Noting that P1 = P2 = Patm, V1 ? 0, the elevation effects are negligible, and the frictional effects are disregarded, the energy equation for the selected control volume reduces to ? P V2 ? ?P V2 ? V2 & & & & & & & m? 1 + 1 + gz1 ? + W pump, u = m? 2 + 2 + gz 2 ? + W turbine + E mech,loss > Wfan, u = m 2 ? ? ? ? 2 2 2 ? ? ? ? Substituting, ? V2 ? 1 kW ? (21. 7 m/s) 2 ? 1 kN & ? ? & = (4524 kg/s) W unloaded fan,u = ? m 2 ? ? = 1065 kW 2 ? 1 kN ? m/s ? 1000 kg ? m/s ? ? 2 ? 2 ? ? ? ? nloaded (b) We now repeat the calculations for the loaded helicopter, whose mass is 10,000+15,000 = 25,000 kg: V 2,loaded = m loaded g = ? A (25,000 kg)(9. 81 m/s 2 ) (1. 18 kg/m 3 )(176. 7 m 2 ) = 34. 3 m/s & mloaded = ? V&loaded = ? AV2, loaded = (1. 18 kg/m 3 )(176. 7 m 2 )(34. 3 m/s) = 7152 kg/s ? V2 ? (34. 3 m/s)2 & & = (7152 kg/s) Wloaded fan,u = ? m 2 ? ? 2 ? 2 ? ?loaded ? 1 kW ? 1 kN ? ? ? 1000 kg ? m/s 2 1 kN ? m/s ? = 4207 kW ? ? 6-23 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation.If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems Noting that the average flow velocity is proportional to the overhead blade rotational velocity, the rpm of the loaded helicopter blades becomes & V 2 = kn > V 2,loaded V 2, unloaded = & n loaded & n unloaded > & n loaded = V 2,loaded V 2, unloaded & n unloaded = 34. 3 (400 rpm) = 632 rpm 21. 7 Discussion The actual power input to the helicopter blades will be considerably larger than the calculated power input because of the fan inefficiency in converting mechanical power to kinetic energy. -24 PROPRIETARY MATERIAL.  © 200 6 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission. Chapter 6 Momentum Analysis of Flow Systems 6-41 A helicopter hovers on top of a high mountain where the air density considerably lower than that at sea level. The blade rotational velocity to hover at the higher altitude and the percent increase in the required power input to hover at high altitude relative to that at sea level are to be determined. Assumptions 1 The flow of air is steady and incompressible. 2 The air leaves the blades at a uniform velocity at atmospheric pressure. 3 Air approaches the blades from the top through a large area at atmospheric pressure with negligible velocity. 4 The frictional effects are negligible, and thus the entire mechanical power input is converted to kinetic energy of air. 5 The change in air pressure with elevation while hovering at a given locatio n is negligible because of the low density of air. 6 There is no acceleration of the helicopter, and thus the lift generated is equal to the total weight. Air flow is nearly uniform and thus the momentum-flux correction factor can be taken to be unity, ? ? 1. Properties The density of air is given to be 1. 18 kg/m3 at sea level, and 0. 79 kg/m3 on top of the mountain. Analysis (a) We take the control volume to be a vertical hyperbolic cylinder bounded by streamlines on the sides with air entering through the large cross-section (section 1) at the top and the fan located at the narrow cross-section at the bottom (section 2), and let its centerline be the z axis with upwards being the positive direction. r r & & F= ? mV ? ? mV . Noting The momentum equation for steady one-dimensional flow is ? ? out ? in that the only force acting on the control volume is the total weight W and it acts in the negative z direction, the momentum equation along the z axis gives W & & ? W = m(? V 2 ) ? 0 > W = mV 2 = ( ? AV 2 )V 2 = ? AV 22 > V2 = ? A where A is the blade span area. Then for a given weight W, the ratio of discharge velocities becomes V 2,mountain V 2,sea = W / ? mountain A W / ? sea A = ? sea ? mountain = 1. 18 kg/m 3 0. 79 kg/m 3 = 1. 222Noting that the average flow velocity is proportional to the overhead blade rotational velocity, the rpm of the helicopter blades on top of the mountain becomes & n = kV 2 > & n mountain V 2, mountain = & n sea V 2,sea > & n mountain = V 2, mountain V 2,sea & nsea = 1. 222(400 rpm) = 489 rpm Noting that P1 = P2 = Patm, V1 ? 0, the elevation effect are negligible, and the frictional effects are disregarded, the energy equation for the selected control volume reduces to ? P V2 ? ?P V2 ? V2 & & & & & & & m? 1 + 1 + gz1 ? + W pump, u = m? 2 + 2 + gz 2 ? W turbine + E mech,loss > Wfan, u = m 2 ? ? ? ? 1 2 2 2 ? ? ? ? or V2 V2 V3 & & Wfan,u = m 2 = ? AV2 2 = ? A 2 = 2 2 2 1 2 ?A? ? ? W ? ? = ? ? ? A ? 3 1 2 ?A? ? ?W ? ? ? ? ? A ? 1 . 5 = W 1 . 5 2 ? A 15 m Then the ratio of the required power input on top of the mountain to that at sea level becomes & Wmountain fan,u 0. 5W 1. 5 / ? mountain A = & Wsea fan,u 0. 5W 1. 5 / ? sea A 2 ? mountain ?sea = 1. 18 kg/m3 = 1. 222 0. 79 kg/m3 Sea level Load 15,000 kg Therefore, the required power input will increase by 22. 2% on top of the mountain relative to the sea level.Discussion Note that both the rpm and the required power input to the helicopter are inversely proportional to the square root of air density. Therefore, more power is required at higher elevations for the helicopter to operate because air is less dense, and more air must be forced by the blades into the downdraft. 6-25 PROPRIETARY MATERIAL.  © 2006 The McGraw-Hill Companies, Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual, you are using it without permission.Chapter 6 Momentum Analysis of Flow Systems 6-42 The flow rate in a channel is controlled by a sluice gate by raising or lowering a vertical plate. A relation for the force acting on a sluice gate of width w for steady and uniform flow is to be developed. Assumptions 1 The flow is steady, incompressible, frictionless, and uniform (and thus the Bernoulli equation is applicable. ) 2 Wall shear forces at surfaces are negligible. 3 The channel is exposed to the atmosphere, and thus the pressure at free surfaces is the atmospheric pressure. 4 The flow is horizontal. Water flow is nearly uniform and thus the momentum-flux correction factor can be taken to be unity, ? ? 1. Analysis We take point 1 at the free surface of the upstream flow before the gate and point 2 at the free surface of the downstream flow after the gate. We also take the bottom surface of the channel as the reference level so that the elevations of points 1 and 2 are y1 and y2, respectively. The application of the Bernoulli equation between points 1 and 2 gives P1 V12 P V2 + + y1 = 2 + 2 + y 2 ? g 2 g ? g 2 g > V 22 ? V12 = 2 g( y1 ? y 2 ) (1)The flow is assumed to be incompressible and thus the density is constant. Then the conservation of mass relation for this single stream steady flow device can be expressed as V&1 = V&2 = V& > A1V1 = A2V 2 = V& > V1 = V& A1 = V& wy1 and V2 = V& A2 = V& wy 2 (2) Substituting into Eq. (1), ? V& ? ? wy ? 2 ? ? V& ? 2 g ( y1 ? y 2 ) & ? ? ? ? wy ? = 2 g ( y1 ? y 2 ) > V = w 1 / y 2 ? 1 / y 2 ? ? 1? 2 1 2 2 2 g ( y1 ? y 2 ) > V& = wy 2 2 2 1 ? y 2 / y1 (3) Substituting Eq. (3) into Eqs. (2) gives the following relations for velocities, V1 = y2 y1 2 g ( y1 ? y 2 ) 1? y2 / 2 y1 and V2 = 2 g ( y1 ? y 2 ) 2 2 1 ? y 2 / y1 (4) We choose the control volume as the water body surrounded by the vertical cross-sections of the upstream and downstream flows, free surfaces of water, the inner surface of the sluice gate, and the bottom surface of r r r & & F= ? mV ? ? mV . The the channel. The momentum equation for steady one-dimensional flow is ? ? out ? in force acting on the sluice gate FRx is horizontal

Microeconomics and the Law of Supply and Demand Essay

During the simulation of Goodlife Inc. I was able to see how the effects of a lower rent verses a higher rent had on the vacancy percentage. In our simulation the town of Atlantis had only one rental agency with apartments available. There were single family homes available too but the need for renting was with apartments. I got to see how the supply and demand worked with this rental property simulation. The town of Atlantis saw a rise in population which led to a higher demand for vacant units. This caused Goodlife to raise its rent to meet the growing demand for its available units. But as the demand for renting the units fell so did the demand. This meant Goodlife had to lower its rental price to meet the lesser demand for renting. This is a good example of microeconomics. When I looked at the simulation for examples of macroeconomics I found it when the government stepped in to put a cap on the rent amount. In the simulation there was a survey that showed individuals were living outside of Atlantis rather than renting a place in the city limits where they work. As many of us do currently in our own lives we usually can’t afford to live in the city or area where the best jobs are. I am a prime example, I commute 50 miles one way to work as it’s where the best salary is. I live in an area where housing and rents are affordable and the overall cost of living is cheaper too. In the simulation, the government put a cap of $1550 for the monthly rent of a two bedroom apartment. This was meant to allow middle class families and individuals the opportunity to live where they work. Because of the rent cap, Goodlife didn’t rent out every apartment available as profits would not be able to keep up with the maintenance cost of having every uni t rented. When we look at what a shift in supply and demand curve we see that clearly when Lintech Inc. moved into Atlantis creating more jobs. As soon as  Lintech did this it increased the population of Atlantis which was the shift in the supply curve. This was a negative impact for Goodlife as there was more population needing apartments and not enough two bedroom apartments available. The demand curve now goes up because of the population growth and need for more apartments. With Lintech moving into the city and the population now increasing the demand it means that the quantity demand is now more than quantity supplied at the original equilibrium. This also caused a temporary shortage in the market of two bedrooms apartments in Atlantis. Rental rates went up due to the higher demand. Also quantity demand decreased and quantity supplied increases which leads to a reduction of apartments or shortage of apartments. To get to the new equilibrium the adjustment needs to get between the new demand curve and the original supply curve. When the new equilibrium is reached the rental rates are now higher than they were before. This also means that the number of apartments that are demanded and the supply of apartments has also increased. I can apply this supply and demand to my workplace job. When I have a customer that wants to ship more packages with us on a new daily bases I have to look at the new demand. Before their demand for shipping more I didn’t need extra couriers and trucks to handle the day’s deliveries. Now with the new demand I have to get my supply of couriers and trucks at the last minute. This causes me to have to spend more money to rent more vans and hire more employees. Overall my cost go up with the demand of more shipping packages, but so does my profit as I am able to use more supplies to handle the new demand. To better understand how the concept of microeconomics helps me understand the factors that affect shifts in supply and demand on the equilibrium price and quantity I have to look at the competitors and their prices. The bidding for the competition and where it comes across the equilibrium is the point at which the new equilibrium is now. But under the view of macroeconomics it is seen when the jobs and population grew. This effected the increase and decrease on the available apartments. Now the equilibrium  for rentals is higher then it was before the move in by Lintech. So is the number of apartments demanded and supplies has increased. In the simulation we saw how with lower prices meant that the demand was higher. But with the demand for apartments came higher prices. But if the price was to increase too much the demand for apartments would decrease. There is also a possibility that it could remain the same over a short period of time, then decrease if prices didn’t change. This simulation showed lots of possibilities that could exists in today’s world, or at least in Atlantis. We see what price could do to supply and demand for apartments and what demand could do to price and supply. When either is moved or switched leads to various outcomes the will lead an economy like Atlantis to either run out of its supply of apartments or have an increase in supply of apartments because the prices are too high. Reference Microeconomics, Ninth Edition, David C. Colander (2013) University of Phoenix

Environmental Factors Of Oil Industry Environmental Sciences Essay

The Omans Environmental National Strategy motion has moved from the periphery to going a cardinal chief watercourse issue. This model towards Biodiversity and the preservation for natural life in agribusiness, Marine, tellurian, and H2O resources is the 2nd ‘wave that has begun to do a displacement in concern thought. Pull offing environmental facets and impacts consistently is about being proactive instead than reactive towards environmental issues. This merge of ecological and economic factors into the pattern of concern direction is critical to accomplishing Oman s environmental preservation aims, and for MB Holding to turn to these alterations and guarantee sustainability. Our environmental policies and criterions, regulative and enforcement patterns, monitoring, scrutinizing and describing supply the communities the confidence that the environment is being protected. MB Holding has established four environmental mark countries which include waste minimisation and direction, pollution bar, resource preservation, and energy efficiency. We aspire to taking inaugural and in developing eco-friendly solutions to environmental issues that may originate from our merchandises, operations and concern activities. We are responsible for the environment in which we work in, and this dedication is demonstrated throughout our work force, our clients and stockholders relationships. We continually seek to transcend conformity and to minimise resource ingestion, and inauspicious environmental impact, limited merely by technologically and economic viability. MB Petroleum steadfastly believes that the complete integrating of its activities with the local environment is most of import in accomplishing its development aims. The company s HSE civilization is extremely maintained by clear policies, processs and engagement of all employees in placing jeopardies, describing a possible hazard and near girls. In MB Petroleum, all employees and contractors are responsible and accountable for HSE public presentation. HSE focal point countries are based on the communicating, competency, equipments, supervising and behaviour safety through route shows. The primary drive aim is to forestall hurts to people around ; to safeguard the wellness of the employees ; to forestall harm to equipment and assets ; and to protect the environment. Pollution control and issues such as air emanations, effluent taint and the direction of risky waste are critical concerns that require sustained attempts in placing the impacts of merchandises and services throughout their lifecycles, including design, cut down, reuse and recycling of equipment and stuffs. MBPS squads are to the full cognizant of their duties to our clients and community stakeholders and hence committed to a robust waste direction plan throughout all their operations. These environmental sound patterns incorporate decrease in stuffs, risky stuffs segregation, and reclaimable stuffs.Socio Economics and Land UseThe cardinal impact issues can be grouped under four headers: i‚ · struggles in land usage i‚ · viing demand for H2O i‚ · farm animal and wildlife safety i‚ · nuisance, chiefly from dust and litter Conflicts in land usage will happen and necessitate to be recognised. There is small that can be done straight without impacting commercial precedences. Mobile life is traditional in this portion of the universe. Freedom to roll and utilize broad countries of the state is a requirement of nomads. If nomadism is to be preserved as a life style, so some steps may necessitate to be considered in order to guarantee that it is non put at hazard unnecessarily by any proposed developments. The demand for livestock safety must be taken earnestly and processs instigated to guarantee it. Livestock and nomadism are synonymous. The demand for H2O ( drinkable and non-potable ) is nationally perceived as a major issue. PDO produces and consumes measures of both drinkable and non-potable groundwater. There is a demand to guarantee that the present degree of use or demand is non baleful national H2O resources. There is besides a demand to guarantee continued entree to set up H2O points for the local citizens as a societal and cultural duty. Nuisance from traffic and building generated dust and wayside litter are issues, peculiarly in the locality of wadis and colonies. New developments should recognize these possible jobs and allow control steps should be implemented.EcologyThe PDO operational countries cover a broad scope of ecological home grounds with different grades of ecological sensitiveness and preservation importance. However, because of the built-in breakability of the desert environment, with many animate beings and workss populating under conditions of terrible temperature and H2O emphasis, harm is easy caused. As geographic expedition and development of hydrocarbon militias continue, so they will progressively hold more impact on the Interior. A preservation oriented attack to all PDO activities, new developments and Restoration of old sites is indispensable to understate these future impacts. The grade of ecological impact is besides affected by whether or non hydrocarbon militias are really proved and later exploited. This leads to a much greater cumulative ecological impact through the big figure and consequent higher denseness of good sites and production and support installations which may be required. Ecological impacts in these fortunes can be cumulative, long-run and terrible, particularly if happening in countries of preservation importance. In countries where isolated Wellss are drilled and later abandoned, direct impacts on the environment are comparatively localized. PDO has already implemented environmental protection guidelines in two of its countries ( the Arabian Oryx Project country and the Salalah/Jebel Qara country ) aimed at understating impacts. In the Salalah part, impacts upon the environment from PDO geographic expedition good boring have been minimum due to the strict execution of extenuation steps. Other than the development of oil militias, the building of ranked roads and grapevines across PDO s operational country is likely the largest impact PDO has on the ecology. The graduated table and significance of these impacts and associated effects may be important. The possible impacts on land based ecology may be considered relative to the country of land disturbed by a specific activity. By contrast, the greatest possible impacts from coastal and seaward operations are those related to leakage or spillage of oil during geographic expedition and production activities.ArcheologyOman is rich in archeology and has the possible to do a part of importance to the apprehension of both Southern Arabia and the Gulf Region. Paradoxically, comparatively small archeological research has been undertaken in the Near and Middle East. The archeological remains of all periods are a delicate, non-renewable resource and are protected by jurisprudence. The grounds of past human activity can be easy destroyed by deficiency of consciousness or consideration during development of a new undertaking. Wherever possible the best pattern is to continue grounds or remains in situ. Where saving is non possible and development is proposed which will hold an impact on archeology, best pattern is to see extenuation steps against standards associating to the affected site s period, nature, extent, quality and rareness. The bing degree of archeological cognition refering to PDO s operational country is excessively low for a consistent extenuation scheme to be formulated at either a general or site-specific degree. New undertakings and developments may hold to see commissioning a plan of archeological informations aggregation.GeologyOman s geological heritage provides may sites and countries where authoritative geological and alone land characteristics occur. At present, no guidelines exist to help in placing or ranking single sites which may be a ffected by PDO s activities. The importance of specific geological characteristics has merely late been considered in some countries of activity ( e.g. , seismal studies ) . Because of the elaborate cognition of Oman s geology held in PDO, it would be a comparatively straightforward exercising to include a reappraisal of important geological characteristics into the EA procedure. A opinion could so be made on the demand for any specific safeguards which will be required.Hydrology and Hydro-geologySeveral PDO activities, notably boring and production H2O disposal, may ensue in impacts upon H2O resources which are likely to be important. Some residuary impacts may happen and these are likely to be ineluctable even after following all possible extenuation. Any techniques to cut down the sum of production H2O, such as down hole dewatering, should be considered since production H2O disposal is predicted to be PDO s major disposal issue in the extroverted old ages. Drinkable H2O from aquifers is a cherished resource in Oman and any possible for taint is a sensitive issue. It is most of import to confer with Exploration in all affairs associating to hydrogeology and hydrology.Air qualityAir quality effects associated with geographic expedition and building activities tend to be localised and transient in nature. The most important impact normally consequences from the building and usage of entree roads when big measures of dust are generated. In countries remote from any colonies, this dust emanation is improbable to be a major impact. Emissions from lasting works such as big engines, gas turbines, flairs, procedure works and cold blowholes may hold important effects depending upon the propinquity of local population or other sensitive receiving systems. There are methods by which emanation rates can be estimated and modeled to foretell the end point land degree concentrations of major air pollutants ( e.g. , NOx, SOx, CO and hydrocarbons ) . Emissions of nursery gases ( CH4, CO2 ) are non important in footings of local air quality effects. However, entire emanations from these activities need to be considered and their significance evaluated on a national or regional footing. Sour gas emanations need careful appraisal with regard to anchor flat concentration due to the utmost toxicity of H2S.Noise and VibrationNoise impacts are potentially important but this is related entirely to the presence of residential communities which are rare across most of the grant country. Where developments are planned near to urban countries, baseline noise studies should be made. An appraisal of possible noise impact should so be undertaken. Site or undertaking specific noise extenuation may be required in order to avoid future jobs.TrafficThe demand to supply route entree consequences in a figure of environmental effects. A big web of roads has already been constructed throughout PDO s grant country and this web is being continually expanded to run into the demands of oil geographic expedition and production. Construction causes physical harm to the desert environment. In many countries this harm will be lasting. A potentially larger term impact, intensifying that straight caused by PDO, arises through the physique up of conveyance corridors and easing communicating links between colonies which did non be before the new route was built. Invasion into sensitive countries may take to struggles with Oman s preservation aims. Because of the mostly negative environmental effects of route building, it is of import that due consideration is given to understating these impacts through careful planning of paths. Road edifice should be based upon making the minimal substructure needed to fulfill operational demands. The current policy of unfastened entree to roads in the Interior is apt to take to struggles with preservation involvements and should be considered really carefully in new undertakings.DirtsDesert dirts are delicate and can be easy damaged during oil geographic expedition and building activities. The most effectual agencies of understating impacts is to curtail the demand for new sites to be developed through maximizing production from bing Wellss. This can be achieved through boring techniques such as side path boring which are already being used in PDO. The nature of geographic expedition and production activities means that there is considerable possible for localized dirt taint non merely from rough oil but besides from the usage of chemicals, Diesel etc. In add-on, bing methods of sewerage disposal at rig sites and cantonments have the possible to do taint.HazardPossible ConsequenceGaseous emanations of methane ( CH4 ) Global warming/atmospheric ozone addition Gaseous emanations of S oxides ( SOx ) Acid deposition, H2O and dirt acidification Gaseous emanations of N oxides ( NOx ) Atmospheric ozone, acerb deposition Gaseous emanations of azotic oxide ( N2O ) Global heating, stratospheric ozone depletion Gaseous emanations of C dioxide ( CO2 ) Global heating Gaseous emanations of C monoxide ( CO ) Human wellness harm Gaseous emanations of H sulphide ( H2S ) Human wellness harm, odour nuisance Gaseous emanations of volatile organic compounds ( VOC ) Atmospheric ozone addition, human wellness harm Gaseous emanations of organic toxics ( PAH, PCB ) Human wellness harm, ecological harm Emissions of all right particulate affair Human wellness harm, soot deposition Emissions of toxic metals Human wellness harm, ecological harm Emissions of odorous compounds Nuisance Emissions of radiation Human wellness harm, ecological harm Emissions of heat Nuisance, ecological harm Emissions of visible radiation Nuisance Emissions of noise/vibration Nuisance Emissions of CFCs ( CFC ) Global heating, stratospheric ozone depletion Emissions of halons Global heating, stratospheric ozone depletion Spills and leaks of rough oil or distillations Ecological harm, biological harm Emissions of dissolved organic compounds Ecological harm, biological harm, tainting of fish Emissions of soluble heavy metals Ecological harm, biological harm through accretion Emissions of soluble salts Increased salt, biological harm Emissions of boring mud/cuttings/chemicals Ecological harm, biological harm Emissions of organic foods ( NH4, PO4 ) Eutrophication Emissions of suspended solids Ecological harm Emissions of oil and lubricating oil ( O/G ) Ecological harm, biological harm Emissions of hot/cold wastewater Ecological harm Emissions of detergents/solvents/cleaners Eutrophication, ecological harm, biological harm Emissions of pathogens Human wellness harm Emissions of anoxic wastewater Ecological harm, biological harm Land disposal of risky wastes Ecological harm, biological harm Land disposal of domestic wastes Ecological harm, nuisance Land take for operations Habitat loss, ecological harm Energy usage for operations Loss of resources Volume of H2O used Loss of resources Volume of natural stuff usage Loss of resources Soil compression from heavy vehicles Alteration of hydrologyENVIRONMENT FACTORS AFFECTING OMAN TOURISM INDUSTRYThe touristry industry of Oman is one of the turning industry in the state. The capital of Oman was named as the 2nd best metropolis to see by travel usher publishing house Lonely planet. The chief attractive force of Oman touristry is it s natural beauties and it s storied past. Peoples from western states visit Oman in order to interact with the Muslim society who are isolated from the modern universe a long clip before. Geting a visa for sing Oman is besides non really hard. A individual entry degree visa is issued for the tourer who wants to see Oman. This visa is valided for one month merely as it is a tourer visa. A mulct of $ 4 is charged per twenty-four hours beyond the 30 twenty-four hours for the tourer. There are besides express visa, a multiple entry or a common visa for the circuit in Qatar, Dubai and a GCC occupant visa. As we have seen Oman touristry is a flourishing industry, it attracts a big figure of tourer while leads to endanger the environment by emphasizing the states resources such as H2O, land etc. Any state has a limited resources of H2O, land etc. As more & A ; more tourist visit the state, they would get these resources which threatens the states resources for the hereafter as it is limited resources. The authorities of Oman plays a critical function in the development of the touristry industry. Visa limitation was eased by Oman s authorities has lead increase the figure of tourer in the last few old ages while has led to develop in the substructure to run into the demand. The authorities of Oman is concentrating on foreign investing in the undertakings such as Parkss, hotels, eating houses, golf cources etc.The current bound by authorities on the figure of tourer is 50,000 tourer per twelvemonth, but the authorities is be aftering to spread out this bound by 100000 tourer per twelvemonth. Oman state is known for it s diverse environment. In order to pull the tourer they are require to supply better substructure, hotels, eating house, golf cources. This would finally emphasize the states resources such as land, H2O, economic resources etc. Environmental Factors Affecting Tourism Industry Climate Water quality Natural resources Solid waste Culture & A ; heritage Wildlife & A ; Parks Pollution Climate The clime of the Oman is hot in nature. It has a really small rainfall in a individual twelvemonth. The one-year rainfall ranges between 5-10 centimeter in a twelvemonth in the major parts of the state. The bulk of rain falls in the month of January in the Muscat. Dhofar is subjected to the sou'-west monsoon and rainfall is recorded up to 65 centimeter in the rainy season from June to October. Where as the mountain country has recorded more rainfall peculiarly near to the island of Masirah. The clime other than these season is really hot where the temperature ranges from 50-55 degree Celsiuss from may to September. Where as in the winter the temperature goes from 15-23 degree Celsiuss which normally attracts the bulk of the tourer. The other coastral metropolis of salalah is comparatively cool for the 3 months of a twelvemonth which besides is one of the ground to pull the tourer. Consequences shows that the clime of Oman has a positive impact on the touristry industry. Oman Is going a popular vacation finish for the British people because of it s clime. The clime of the state besides makes the golfing most popular in the state. The clime of salalah is cool in nature comparison to the other parts of the state which chiefly attracts the people from European states to tour Oman. Water quality Water, and particularly fresh H2O, is one of the most critical natural resources. Oman depends on groundwater and it s limited rainfall for H2O. As more & A ; more people are touring the state the demand for the H2O rises. As H2O is a limited resources, it consequences into the deficit of H2O. In order to fulfill the deficit of H2O more & A ; more H2O purifiers are being used which increase the quality of H2O. Oil is besides an of import resource of the state. Oman transports more than 50 per of the oil produced in the universe through the sea of Oman. This besides consequences into the oil related pollution in the quality of H2O. 94 % of available H2O is used in farming and 2 % for industrial activity, with the bulk sourced from fossil H2O in the desert countries and spring H2O in hills and mountains. Decrease in the quality of H2O has a negative impact on the touristry industry. As more & A ; more undertakings for bettering the quality of H2O are being approved by the authorities, but still impacts negatively on the touristry industry. Natural resources Oman has a best natural resources to pull the tourer. It has the best threatened species included 12 types of mammals, 14 species of birds, 4 types of reptilians, 18 species of fish, 1 species of invertebrate, and 6 species of workss. Decrees have been passed in order to protect endangered species, which include the South Arabian leopard, mountain gazelle, goitered gazelle, Arabian tahr, green sea polo-neck, hawkbill polo-neck, and olive polo-neck. The archeological park are created in order to protect the natural resources of the state & A ; to pull tourers in the state. It is besides to inform people of this of import ancient metropolis in the Governorate of Dhofar. Oman has a 5000 old ages of history, encompassed within archeological sites, ancient architecture and alone mosques etc. Oman has the best natural resources to pull the foreign tourer in the state. It has over 500 historical garrisons, many mountain scopes, and a exuberant southern part – it means it has all the characteristics that the other gulf states are missing. The state already attracts a good figure of visitants from the Gulf Cooperation Council ( GCC ) provinces who are looking to get away the heat. In February 2004, the Omani authorities planed calls for the edifice of a marina, a five-star watering place and beachfront hotel, premium Villa, and a golf class on 7.3 kilometer of beachfront merely west of Muscat. The Wave will be the most ambitious tourer undertaking attempted in the state and now pulling a immense figure of tourers. Two other resorts, the Barr al-Jissah Resort and the Muscat Golf and County Club, besides provide ample private lodging. Large-scale resorts are besides being planned near Salalah in Dhofar. Oman has traditionally targeted wealthier Europeans. These visitants – normally composed of smaller groups – have by and large been thought to possess a greater sensitiveness to the more conservative facets of Omani society. Specifically, they are less likely to do the jobs with intoxicant normally endemic in big resorts and on bundle Tourss. Solid waste The state is traveling towards zero waste which has positively consequence on the touristry industry. Developing states are now a yearss seeking to do usage of the solid waste by recycling the waste through assorted engineerings. OESHCO ( oman environmental services keeping company ) is responsible for all cardinal waste direction countries including waste aggregation, transit, separation, and processing, recycling, incineration, land-filling, handling of solid, industrial ( risky and non-hazardous waste ) and medical waste and redress of environment tonss. As portion of this reconstituting plan, some major structural alterations may happen within Oman s waste direction sector including current entities being reorganized, new entities established, engagement of private sector through denationalization. OESHCO will set about the execution of the authorities s policy with respects to the direction and operation of the waste sector s activities in conformity with the national scheme being planned by the Ministry of National Economy. The state is endeavoring to set up 16 engineered landfills, 65 waste transportation Stationss and 4 waste treatmentA workss in different parts of the state by 2015.A Culture & A ; heritage Heritage The bequest that is been passed from one coevals to other such as art, civilization, folklore and the prowess has been a major attractive force for the tourer. But it has lot more to offer. The people are quiet in nature. They have regard for clip, and for nature. The gustatory sensation of the oman s rich heritage, kept alive and remains unchanged for coevalss. It boasts an high figure of UNESCO-classified World Heritage Sites including Al-Blaid ; site of the ancient metropolis of Zafar, Bat- with is known dating back 3,000 old ages, Bahla Fort, and Ras Al-Hadd ; place to the rare Green Sea Turtle. Oman ‘s heritage features a singular sea-faring tradition. There are many museum & A ; galleries are present in the metropolis of Muscat and Muttrah which shows the importance of the sea and of H2O by and large, throughout Oman ‘s 5,000 year-old history. So, the heritage of Oman has a positive impact on touristry industry & A ; attracts a batch of tourer around the universe. Culture The state has an good civilization and traditional life style of the people populating in. Even in the modernisation Oman is an Arabic state and offers a assortment of alone admirations. The Omani civilization has its roots steadfastly deep in the Islamic faith. Oman people are stuborn of the beliefs of different Muslim divisions.But they are besides tolerant towards the believes of other religions of people who are allowed to pattern their faith in churches and temples such as Indians. Moslems are required to pray five times each twenty-four hours after the call to prayer by the Imam. Ornate mosques are found throughout the Sultanate, but they are merely unfastened to the Muslim visitants. The holy month of Ramadan is a clip of fasting and praying. For around 29 to 30 yearss each twelvemonth, Muslims refrain from smoke, feeding and imbibing during the hours of fasting ( from dawn to sunset ) . So the people from non-Muslim occupants and visitants to the Sultanate are expected to detect the same rules in public. Wildlife & A ; Parks Oman has a wildlife, both on land and on the Waterss. The authorities has created rigorous Torahs in order to protect the animate beings such as the Arabian leopard and the Arabian Oryx. Nature militias have been set up throughout the Sultanate to protect the natural home grounds of mammals such as the leopard, Oryx, gazelle, taher, ibex, desert foxes and wild cats. The Waterss are place to 22 species of giant and mahimahi. Turtlenecks are attracted to Oman ‘s shores and capsize genteelness militias are located at Ras al-Jinz and the Dimaaniyat Islands. Oman has a great marine life and some of the best honkytonk sites in the universe. In peculiar, the Hallaniyat Islands and the Dimaaniyat Islands offers opportunities to see attractively coloured fish and unusual difficult and soft corals. Approximately 400 birds have been recorded in Oman during the seasons. Because the location of the state is at the hub of three different geographical land multitudes, It is host to many foreign species, such as the Golden Oriole, Nightjar and White Stork. In the genteelness season, public entry is prohibited to the Dimaaniyat Islands, where there is a bird sanctuary. During September to November, many bird of Joves migrate to Oman, such as the Imperial Eagle and the Greater Spotted Eagle. Oman is typically considered to be a ‘desert state ‘ , Oman astounds the visitant with its gardens, and luxuriant flowered shows run alonging the main roads and bypaths. All the Parkss are free to come in and normally have little bite stores or drinks stands available in it. Muscat has a several Parkss that varied in countries and location. The chief Parkss are Qurum Natural Park, Riyam and Al Naseem. Generally the Parkss attracts a batch of people because of the acuteness for seting trees inside these Parkss and increasing the green countries, the affair which encourage more people to bask sing them during official vacations. So the wildlife & A ; assortment of gardens of the state plays a critical function in pulling a immense figure of tourer around the universe.ENVIRONMENTAL FACTOR OF GAS INDUSTRYSustainable development is guaranting that our present demands do non compromise the demands of our future coevalss. This method represents a various attack to pull offing our environmental, economic and societal resources for the long term. Our environmental aim for 2008 is to committee the 20 MMSCF capacity gas intervention installation, and recover the gas from the B Block production installation and Daleel Production Station, direct it to the gas intervention installation. The expected outputs from the gas intervention are about 400-500 bpd of liquefied crude oil gas and 500-600 bpd of NGL. Daleel is be aftering to committee the gas works this twelvemonth, and the first measure of the gas flaring is to cut down it from 13 MMSCF ( Current Production ) to 6 MMSCF. The ultimate purpose is to retrieve the gas watercourse and thin gas, which will be partially used for the centralised power coevals works and the thin gas will be re-injected back in the bing gas cap in the C-block, ready for flame uping. Petrogas recognizes that this invention is a critical ingredient for the protection of communities and additions company fight within the oil and gas sector. Petrogas is emerging as an industry leader in clean gas production and contributing to environmental protection and pollution bar, by cut downing degrees of hydrocarbons.A The Section of Environment, Energy, and Resources is the Prime Minister forum for attorneies working in countries related to environmental jurisprudence, natural resources jurisprudence, and energy jurisprudence. The Section is committed to supplying members with chances to heighten professional accomplishments, remain on top of current developments, and duologue in these substantial countries. Section rank will add to your professional accomplishment set and broaden your cognition. Clean Air Act The Clean Air Act ( CAA ) is the comprehensive federal jurisprudence that regulates air emanations from stationary and nomadic beginnings. Among other things, this jurisprudence authorizes EPA to set up National Ambient Air Quality Standards ( NAAQS ) to protect public wellness and public public assistance and to modulate emanations of risky air pollutants. Clean Water Act The Clean Water Act ( CWA ) establishes the basic construction for modulating discharges of pollutants into the Waterss of the United States and modulating quality criterions for surface Waterss. The footing of the CWA was enacted in 1948 and was called the Federal Water Pollution Control Act, but the Act was significantly reorganized and expanded in 1972. â€Å" Clean Water Act † became the Act ‘s common name with amendments in 1977. Energy Policy Act The Energy Policy Act ( EPA ) addresses energy production in the United States, including: ( 1 ) energy efficiency ; ( 2 ) renewable energy ; ( 3 ) oil and gas ; ( 4 ) coal ; ( 5 ) Tribal energy ; ( 6 ) atomic affairs and security ; ( 7 ) vehicles and motor fuels, including ethyl alcohol ; ( 8 ) H ; ( 9 ) electricity ; ( 10 ) energy revenue enhancement inducements ; ( 11 ) hydropower and geothermic energy ; and ( 12 ) clime alteration engineering. For illustration, the Act provides loan warrants for entities that develop or use advanced engineerings that avoid the by-production of nursery gases. Another proviso of the Act increases the sum of biofuel that must be assorted with gasolene sold in the United States. Environmental Law Institute The Environmental Law Institute provides information services, advice, publications, preparation classs, seminars, research plans and policy recommendations to prosecute and authorise environmental leaders the universe over. ELI s audience is taking environmental professionals in authorities, industry, public involvement groups and academe Natural Resources Defense Council ( NRDC ) NRDC is the state ‘s most effectual environmental action organisation. We use jurisprudence, scientific discipline and the support of 1.3 million members and on-line militants to protect the planet ‘s wildlife and wild topographic points and to guarantee a safe and healthy environment for all living things.OMAN LNG FACTORSOman Liquefied Natural Gas LLC ( Oman LNG ) is a limited liability incorporated joint venture company established by a Royal Decree and operated under the Torahs of the Sultanate of Oman. It engages in the concern of bring forthing and selling Liquefied Natural Gas ( LNG ) and byproduct Natural Gas Liquids ( NGLs ) . The Company undertakes, straight or indirectly, undertaking operations and activities necessary to liquefy, shop, conveyance and market Oman s natural gas and to present LNG to clients. The Company operates 3 liquefaction trains – 2 owned by Oman LNG LLC and 1 by Qalhat LNG SAOC – at its site in Qalhat near Sur with a nameplate capacity of 10.4 million metric tons per annum. The Company s activities contribute to the Government of Oman s aim of diversifying the economic system off from its current dependence on oil. Oman LNG s Head Office is in Muscat an the works is located on the seashore of Qalhat near Sur, in the Sharqiyah part.Our Core Valuess:1. Achieving HSSE ( Health, Safety, Security and Environment ) Excellence 2. Meeting our Commercial Challenges in partnership with our providers and purchasers 3. Prolonging Operational Integrity in everything we do 4. Attracting, Developing and Retaining the Right Endowment 5. Promoting our Brand, Enriching our Corporate Culture and Repute 6. Delivering Cost Leadership and 7. Guaranting Organizational Effectiveness Since our 1st lading in 2000, the Company has delivered ten old ages of of all time bettering returns on investing to our stockholders, uninterrupted supply of LNG and NGL to our clients, growing in the professionalism, experience and acknowledgment of our staff and a alone partnership with the authorities and people of Oman in support of sustainable economic autonomy and variegation. We intend to construct on what we have achieved, to research new avenues of chances in readying for future concern growing when the external environment allows and to construct upon our successes to procure our hereafter. The betterments that direction and staff are committed to accomplishing are captured as specific, mensurable, conveyable, realistic and time-framed cardinal public presentation indexs ( KPI s ) , some of which are presented in this one-year study.Individual Integrityoˆ‚? Populating the OLNG values oˆ‚? Making what is right even if: oˆ‚? No 1 is looking oˆ‚? You know you could acquire away with somethingProfessionalismoˆ‚? Producing quality work at all times oˆ‚? Efficiency and effectivity in transporting out assigned functions and dutiesAccountabilityoˆ‚? Delivering on promise based on in agreement marks oˆ‚? Showing ownership of mandated assignmentsOrganization Team workoˆ‚? Collaborating with others to present on organisational aims oˆ‚? Value differences and purchase on diverseness of the squadCare & A ; Respectoˆ‚? Listening to concerns of stakeholders oˆ‚? Respecting diverseness oˆ‚? Sing stakeholders demandsAuthorizationoˆ‚? Having assurance and trust in delegated duties to staff to put to death undertakings aptly oˆ‚? Coaching and mentoring to continuously develop staffBusinessTransparency & A ; Fairnessoˆ‚? Engage staff/stakeholders in an unfastened, crystalline and timely mode oˆ‚? Provide equal chance to all staff without bias oˆ‚? Impartiality in staff wages and acknowledgment oˆ‚? Build bravery to give nonsubjective feedbackReputation/ Loyaltyoˆ‚? Conformity with the jurisprudence and concern rules in order to keep credibleness with stakeholders and the licence to run oˆ‚? Uphold concern involvements at all times without transgressingEnvironmentBeach cleansing is a frequent activitySafetyEveryone has a function to playConformityRecipient of GCC s Best in Compliance to Environmental Standards Award Health, Safety, Security, Environment Quality HSSEQEXCELLENCE In 2009, Oman LNG continued its resoluteness for uninterrupted betterment in HSSE public presentation. Some of the high spots achieved were:Healthoˆ‚? Staff medical fittingness confidence: Oman LNG achieved 97 % against a mark of 85 % in 2009.Safetyoˆ‚? 0.6 Million Man-Hours achieved without a Lost Time Injury ( LTI ) by terminal 2009. oˆ‚? LTIF for 2009 was 0.72. oˆ‚? Introduced the 12 Life-Saving Rules that clearly define the â€Å" do s and wear T † in the activity countries with the highest potency for injury to people. The 12 regulations are being enforced to guarantee conformity by everyone who works with Oman LNG and allows them to return place safely every twenty-four hours. oˆ‚? 3 major runs amongst staff and contractors on: oˆ‚? Road Safety. oˆ‚? Good House Keeping. oˆ‚? Hazard Awareness. oˆ‚? Executed 6 care closures without LTI or TRC ( 3 Trains and 3 GTGs ) .Securityoˆ‚? Oman LNG completed the installing of new ‘state-ofthe- art security installations and systems to safeguard company assets and people. The undertaking was based on extended advice from the Royal Oman Police and our Security Advisors.Environmentoˆ‚? Oman LNG won the desired GCC Award for Conformity with Environmental Regulations in late 2008. oˆ‚? Company is to the full compliant with MECA demands in all its environmental licenses and â€Å" Licenses to Operate † . oˆ‚? No environmental incident occured in 2009. oˆ‚? Very low ( pacesetting ) flame uping rates, averaging 0.23 % of entire feedgas to works in 2009.Qualityoˆ‚? Successful re-certification audits of our: oˆ‚? ISO 9001:2000 Quality Management System. oˆ‚? ISO 14001:2004 Environmental Management System. oˆ‚? Successful re-certification audits of our: oˆ‚? ISO 17025 Laboratory Management System Brand & A ; Reputation 2009 continued to be another active twelvemonth in all countries of the Social Investment by the Company. Some illustrations of Oman LNG s parts:Healthoˆ‚? Supplied portable bosom echo-cardiograph system to Royal Hospital. oˆ‚? Supplied equipment for the Cancer Center at Royal Hospital & A ; Cytogenetic Laboratory at Khoula Hospital. oˆ‚? Funded the purchase and installing of equipment for a specialized Ear, Nose & A ; Throat ( ENT ) preparation research labEnvironmentoˆ‚? Construction of protection barriers in the Wilayat of Wadi Bani Khalid against carnal invasion. oˆ‚? Rearing of White Goats in Jabal Al Abiyadh, Heil Al Harem, and Wilayat of Dima Wa Al Tayeen.ENVIRONMENTAL FACTOR OF AGRICULTURE AND FISHING INDUSTRYAgribusiness, farm animal and piscaries are among the oldest and most of import sectors of theA Omani economic system. They play a critical portion in feeding the population, supplying employment for big Numberss of Omanis and assisting to hike the state s GDP. The Batinah Region has the most day of the month thenars, Mangifera indica and calcium hydroxide trees, while the Governorate of Dhofar has the most coconut thenars. Agricultural advice and counsel programmes have been adopted to advance the usage of high-quality fertilizers and seeds, modern irrigation systems have been introduced on the farms and barriers have been built to supply protection against wadi inundations. Fisheries: With a coastline over 1,700 kilometers long, Oman is one of the chief fish-producing states in the part and theA piscaries sector is among its most promising sectors. Fishing is one of the state s oldest businesss. Fish agriculture is now a turning industry and a fish agriculture Centre is presently being set up, while the quality of the gimmicks is being improved, following the creative activity of the Fisheries Quality Control Centre. Marketing operations have been streamlined across the state and exports are now better regulated, peculiarly with respect to certain types of rare, high value fish. Fisheries developing Centres have been established in Al Khabourah and Salalah, informations and statistics on the fishing industry have been upgraded and new fishing seaports have been built and equipped with modern installations ; today there are angling seaports along the Omani seashore. The Seventh Five-year Development Plan ( 2011-2015 ) is committed to developing and keeping the Sultanate s aquatic resources, guaranting that the fishing evidences and coastal countries are decently managed, regulated and monitored. The Indian Ocean Rim Association for Regional Cooperation ( IORARC ) s Fisheries Support Unit is based in Oman. The unit promotes cooperation between member provinces in the direction of this critical – and renewable – resource. The Ministry has late carried out a programmed to better, develop and diversify the cultivation of field harvests and fresh fishs, with the purpose of placing the best local strains and bettering them. Under the programmed, new types of field harvests and fresh fish were evaluated and introduced to the Omani environment. Other aims included the readying of coders aimed at increasing the grain production of the field harvests and bettering field harvest cultivation methods. The programmed covered wheat, barley, fresh fish, Lucerne and silage. Research has been advanced in the survey of plagues and of works diseases. Particular attending has been given to diseases which attack calcium hydroxides, day of the month thenars, coconuts, bananas and tomatoes. Programmers have besides concentrated on biological bar methods. The Ministry provides the Omani husbandman with a figure of services which he is unable to set about on his ain, and which require high proficient and other installations. Spraying squads from the Ministry have been runing over big countries of day of the month gardens against a detrimental day of the month thenar chow ( mataq ) . They have besides been helping husbandmans in protecting their Fieldss with the usage of general pesticides. The Ministry besides offers farm ersploughing services for nominal hire charges at its agricultural development centres. New ordinances on agricultural and livestock subsidies were issued in 1992. The Ministry subsidies the cost of agricultural mechanical equipment to promote husbandmans to utilize it. Items covered include Big Dippers, harvesters, binders, chemical sprayers, mechanical proverb and little agricultural implements. Other subsidies cover chemical fertilizers, seeds, pesticides, fruit seedlings, plastic screens, cloches and compost. The Government has besides reduced unit monetary values of electricity and Diesel used for farming and agricultural industry undertakings. The policy of the Oman Agriculture and Fisheries Bank is to supply loans for all classs of husbandmans, with precedence being given to little husbandmans and productive agricultural undertakings. The Bank besides ad curates some agribusiness and piscaries loan programmes, and grants loans in cooperation with the relevant sections of the Ministry. Until duty was transferred to the Ministry of Water Resources at the beginning of last twelvemonth, the Ministry of Agriculture and Fisheries was responsible for the care of aflaj and the con struction of recharge dikes. The Ministry continues to work closely with the Ministry of Water Resources in doing the best usage of available H2O resources. During the current Five-Year Plan the Ministry has implemented a figure of undertakings, including a programme to de termine which land is suited for agribusiness, a survey of the south Ba tinah, where peculiar irrigation jobs have arisen, and a survey of the Salalah Plain in the South, with a position to presenting modern methods o f irrigation on farms. One of the Sultanate ‘s major, and most promising, programmes is the debut of nursery engineering. The Ministry has begun subsidising undertakings of this types, and intends to concentrate on green house agribusiness in its following Plan.A The Sultanate of Oman occupies the eastern corner of the Arabian Peninsula, stretching more than 1700 kilometer from the Strait of Hormuz in the North to the frontiers of Yemen in the South. The Musandam Peninsula, the most northern point of Oman is separated from the remainder of the state by Fujaira, which is one of the United Arab Emirates. The state is located between latitudes 16o 40 N and 26o 20 N and longitude 51oE and 59o 40 E. It occupies entire country of about 309,500 sq. kilometer, of which mountains, comeuppances and coastal fields represent 16 % , 81 % and 3 % , severally. It can be divided into the undermentioned physiographic parts, i. the whole coastal plain- the most of import parts are the Batinah Plain in the North, which is the chief agricultural country, and the Salalah Plain in the South ; two. the mountain ranges- that run in the north near to the Batinah Plain is the Jebel Al Akhdar with a extremum at 3,000 metres and in the utmost southern portion of the sta te, with extremums from 1,000 to 2,000 metres ; and iii. the internal regions- which lay between the coastal field and the mountains in the North and south consist of several fields with lifts non transcending 500 metres. The clime varies from arid in the interior parts, to humid in coastal countries to tropical in the southern parts of the state with a temperature scope from below nothing ( in Jebel Akdar and Jebel Shams ) to 50oC in summer in the desert. The mean one-year rainfall is about 100 millimeters, largely distributed between November and February, except in the Dhofar part where there is monsoon rainfall ( 200-250 millimeter ) during kharif ( July-September ) period. Agribusiness and Fisheries merchandises are among the chief non-oil trade goods that account for about 22.7 % of Oman non-oil exports in 2005 ( www.moe.gov.om ) . The agricultural merchandises that are exported include chiefly dried and fresh day of the months, dried calcium hydroxides, fresh fruits, and veggies. Over the past old ages, the authorities has made concerted attempts to better productiveness in agribusiness through modern irrigation techniques and harvest farming patterns. As a consequence, during the last decennary the production of day of the months has increased by 30 % while outputs of tomatoes, murphies, and alfalfa hold doubled. With the population increasing yearly at a rate of more than 3.28 % , there is a demand for increasing nutrient production and new schemes are being explored for accomplishing sustainable nutrient security.Agro-ecological parts of OmanTwo chief agro-climatic zones are recognized in Oman based on parametric quantities which influence potency of land, H2O resources and cropping forms: Northern Oman including Batinah Coastal field, Interior Oman and Dahira fields, Jebel Akhdar and Sharqiya fields. Southern Oman, Dhofar including Salalah field, Dhofar Jebel and Najd. 10Northern Omantraditional inundation system still remains the most common irrigation technique, which accounts to about 80 % . Oman has a broad diverseness of harvest workss for diet and nutrient or provender intent in add-on to other human usage. A figure of field harvests, veggies, fruit trees, forest trees, rangeland grazing land species, aromatic and medicative works species are autochthonal and known to be grown in the Sultanate since immemorial clip. Table 2 lists chief species for nutrient and agribusiness of Oman. Among these the most of import 1s are day of the months, banana, acerb calcium hydroxide, Mangifera indica, wheat, barley, garbanzo, onion, garlic, sweet murphy, Cucumis sativus, Citrullus vulgaris etc. With the exclusion of corn, oats, and sunflower, all the other species are considered autochthonal. Oman has non merely several local adapted cultivars and land races or ecotypes of harvest species such as Coola, Missani, Humaira, Walidi etc in wheat but besides wild relations of some harvest workss that form the beginning of stuff for harvest genteelness to reassign specific characters. Although systematic in situ and on-farm studies on the province of inter and intra-specific works diverseness have non been sufficient, there is grounds of an increasing force per unit area from several abiotic, biotic and societal factors on this diverseness. These factors include: I. Soil and H2O salt ; two. Overgrazing and deforestation of rangelands, three. Replacement of local cultivars by high giving modern cultivars ; four. Climate alterations doing utmost high temperatures and drouth ; v. Plagues and diseases, particularly viruses and virus-like diseases ; six. Urbanization of the exterior range/ cragged lands ; and, vii. Scarcity of irrigation H2O impacting farming diverseness. The state is transporting several activities sing preservation of works familial resources for nutrient and agribusiness which are as follows. 1. Surveying, stocktaking, and aggregation of PGRFA- since late 1980s. MAF has collected independently and in coordination with international organizations/institutes autochthonal germplasm accessions of veggies, fruits, eatages and grazing lands harvest workss ( Guarino, 1989 ) . Besides the Ministry of Heritage and Culture, Royal Gardens and Farms of the Directorate General of Agriculture & A ; Veterinary of the Royal Court and Sultan Qaboos University have been either keeping botanical gardens affecting autochthonal works species or printing the position of vegetations and zoologies and checklists of works species in the state foregrounding the endangered species 2. MAF is involved systematically in seed production of autochthonal harvest landraces and selected grazing land grass species and generation of seedlings of fruit tree species since 1980s and production of day of the month thenar outgrowths and banana seedlings through tissue civilization since 1990s. 3. MOA and Royal Gardens and Farms of the Directorate General of Agriculture & A ; Veterinary of the Royal Court, are presently pull offing several field genebanks of fruit and rangeland species. Seed Technology Unit of MoA has been late upgraded to National Gene Bank of Plant Genetic Resources. 4. Under the Royal Decree 6/2006, initial activities have been started to set up the Oman Botanic Garden in Seeb, Muscat by the office of the Advisor for Conservation of the Environment, Diwan of Royal Court. These included listing and collection of the mark works species. In situ preservation and direction of PGRFA in the state are carried out by both MoA and Ministry of Environment and Climatic Affairs ( MECA ) . MoA is concentrating on the preservation and direction of autochthonal landraces of field harvests, veggies, and grazing land works species, whereas MECA has reserved countries in different parts of the state with purpose of conserving the ecosystems..AENVIRONMENTAL FACTOR SUMMARYFast frontward to – in the close hereafter – a universe in which environmental costs are to the full internalized into the procedures of large concern. Those companies that have their systems ready now, and that are presently doing concern determinations around C costs, energy efficiency and H2O ingestion, will be good placed to harvest really important benefits in the hereafter. Water is indispensable to the hotel industry. Meanwhile, planetary ingestion of H2O is duplicating every 20 old ages, more than twice the rate of human population growing. Sup ply Tourism in a finite universe is finite, and yet demand has risen steadily as populations grow and ingestion per capita additions. With 22 % of planetary demand for fresh H2O coming from industry, pull offing H2O more efficaciously is a necessity instead than an option. Arguments over the finite nature of fossil fuels may be less distinct, but with a consensus on clime alteration driving both a displacement in client sentiment and alterations in statute law ( for illustration, the UK s new â€Å" CRC Energy Efficiency Scheme † introduced in April this twelvemonth ) , the demand for concern to cut down its ingestion of oil and gas, and to put in new energy beginnings, is copiously clear. The hotel sector is energy-intensive, disbursement over ?1bn each twelvemonth on energy and bring forthing 3.5m tones of C emanations yearly in the UK entirely, harmonizing to the Carbon Trust. Using cleaner and cheaper energy beginnings will assist non simply to cut down operational costs, but to increase fight and sustainability into the average term. Starwood is working toward both a 30 % decrease in energy usage and a 20 % lessening in H2O ingestion per available room by 2020. At their Aloft Hotel in Abu Dhabi, more than 90 % of the hot H2O at the 408-bedroom hotel will be supplied through energy from solar panels, salvaging an estimated 870 mega watt hours of electricity every twelvemonth. At Starwood s St Regis Aspen Resort, one of the first hotels in America to utilize e-tube solar engineering which utilizes the Sun as a natural heat beginning, they have installed over 1,300 solar e-tubes on the roof since the terminal of 2008. Component, Starwood s â€Å" green from the land up † trade name, made its ain history by going the first major hotel trade name to mandate that all belongingss pursue LEED ( Leadership in Energy and Environmental Design ) Certification. In-room recycling bins, water-efficient spigots and fixtures and eco-friendly pigments, rugs and furniture all contribute to the green docket. Alternatively of utilizing electric warmers to cut down humidness, Hyatt Regency Dubai uses hot air from the out-of-doorss to reheat the air in the air-handling units ( AHUs ) , roll uping an impressive 15,000 gallons, about, of condensate H2O per twenty-four hours from all AHUs and hotel room fan spiral units, which is so used in the chilling tower. In 2007, the Grand Hyatt Dubai implemented one of the largest solar panel installings in the Middle East, ensuing in a 50 % decrease in monthly fuel costs and a 4.5-year payback period. The hotel has since continued to spread out the system. And over in Singapore, Grand Hyatt is doing usage of Hyatt s Trigeneration Project that works by capturing wasted heat from generators and utilizing it to bring forth hot H2O, steam and infrigidation. The UK s largest hotel and eating house grou p has unveiled programs for a new green hotel and its first low C eating house, due to open in Burgess Hill, UK, in Autumn 2010. The development will utilize rainwater harvest home and gray H2O recycling for 100 % of its lavatory H2O usage, presenting a 20 % salvaging on the hotel s full H2O ingestion. Both the hotel and eating house will be built utilizing lumber frame building methods from sustainably sourced wood, leting for high degrees of insularity to accomplish ‘Turning surging temperatures into an environmental advantage – Hyatt Hotels and Resorts ‘New â€Å" green † hotel and a pledge to cut down C emanations by 26 % by 2020 – Whitbread ‘Reducing the C footmark by 25 % by 2017 maximal energy efficiency. Marriott International is presenting a green hotel paradigm that will be recertified by LEED, an internationally recognized green edifice certifi cation system designed by the US Green Building Council. By implementing these H2O effi ci ency steps, plus wash-on-request linen and towel policies and water-efficient kitchen and wash installations, Marriott estimates that H2O ingestion of a typical 100,000 ft2 ( 9290.30m2 ) select-service hotel will be reduced by over 3.8m liters per twelvemonth, salvaging 10s of 1000s of dollars per twelvemonth. Marriott s Courtyard Portland City Center ( LEED Gold Certificate ) is designed to utilize 30 % less energy, cut down H2O ingestion by 26 % and recycle or recycle 84 % of building waste. The International Tourism Partnership has a strong function to play in foregrounding best pattern in sustainability within the hotels sector, and in pressing the instance for farther alteration if the industry is to boom into the longer term. The good intelligence is that these issues are now steadfastly embedded on the dockets of the boards of many of the taking concerns in the sector. However, most of the steps that are either being planned or are already in topographic point point to incremental alteration over a figure of old ages. Examples of system-wide â€Å" riotous invention † that re-define the basic concern theoretical account ( built on premises of continual volume growing ) are harder to happen. And for both consumers and corporate looking to do determinations with the lightest possible environmental impact, the comparison of the many options available remains a important challenge. Oman is endowed with its rich biodiversity as it has non merely diversified traditional agribusiness affecting about all types of harvest species but besides huge rangelands particularly in Dhofar holding assorted grazing land species. It has broad diverseness of harvest workss for diet and nutrient or provender intent in add-on to other human usage. Some field harvests, veggies, fruittrees, forest trees and rangeland grazing land species have been autochthonal and known to be grown in the Sultanatesince clip immemorial. Oman has non merely several local adapted cultivars and land races or ecotypes of harvest species but besides wild relations of some harvest workss that form the beginning of stuff for harvest genteelness to reassign specific characters.

Buffalo Hunt Essay

It was one sunny hot afternoon, when First Nation people gather and tried to observe for buffalo. They are thinking of strategies and steps on how they would kill for it. I even saw that they used a telescope in order to watch and look in a clear view. I heard conversation in which everyone was giving an opinion on what they saw. Kicking Bird and his troupe decided to buffalo hunt. Hunting is a big part for First Nation people. It is a ritual doing or a tradition. It is an ancient and time-honoured tradition, which helps us stay in touch with our roots. It also allows us to experience the link between men and animal in an intimate way, and to procure our food more directly .They hunts to live, and live to hunt. Later on, they went back to their places and tell the community that they will go for buffalo hunting. I had seen that their families are very supportive and happy. While the hunters are getting ready, everyone was excited and was not able to hide the feelings on how hunting is important in their tradition. They all started to gather all their weapons used for hunting. I have witness how their family and friends gave them the courage, strength and prayers that they needed. The yelling and loud voices of the people made me feel alive. The hunters started to leave with a passion in their heart on what result may it be. While on the way to/

The Great Depression Assignment Example | Topics and Well Written Essays - 500 words

The Great Depression - Assignment Example This led to an increase in inventories while agricultural income remained relatively low. Federal regulations on the US businesses contributed to the Great Depression. This is especially because taxes laws were made favorable to large corporations. Macroeconomic policies never existed, and there was the absence of fiscal and monetary policies. Laissez-faire and hands off government were the watchwords used by the leaders. The Great Depression ended when the Federal Government of the United States imposed rationing, recruited around 6 million defense workers who included African Americans and women, ran massive deficits in order to fight World War II and drafted 6 million soldiers. Deficit spending, inflating the supply of money and the new deal of the federal government also cured the Great Depression. World War II also cured the Great Depression. The Great Depression ended in December 1941 at the same time when the World War II began. The economy had  been expanding since 1938, just less than three years before the country’s entry into the Second World War and the economy stopped expanding in 1945 before the war ended. During the war, the economy of US was a huge arsenal which led to the deterioration of the consumers well being. However, after the war, a genuine prosperity returned in the economy for the first time since 1929 making the war a cure of the Great Depression. Hebert Hoover was blamed for the Great Depression as he was not involved in the stock market issue. The depression affected him so much that he had to give much that he had to pull out his money from the stock market. He did not give government aids to the people for fear of inflating the budget of the Federal government and was forced to break off from the laissez-faire policy which was used to deal with depressions and recessions in the country. He was forced to spend more of the country’s income to help in economy rebound like the construction of the